In the figure, a 5.40 kg block is sent sliding up a plane inclined at e = 37.0° while a horizontal force F of magnitude 50.0 N acts on it. The coefficient of kinetic friction between block and plane is 0.320. What are the (a) magnitude and (b) direction (up or down the plane) of the block's acceleration? The block's initial speed is 4.10 m/s. (c) How far up the plane does the block go? (d) When it reaches its highest point, does it remain at rest or slide back down the plane?
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- A force P = 977 kN whose line of action passes through points A(1, 2, 3) and B(7, 8, 6). Determine the x-component of force P in kN. Write the numerical value only and in 2 decimal places.Chapter 06, Problem 026 GO Z Your answer is partially correct. Try again. The figure shows three crates being pushed over a concrete floor by a horizontal force F of magnitude 631 N. The masses of the crates are m, = 31.0 kg, m, = 10.0 kg, and m3 = 20.0 kg. The coefficient of kinetic friction between the floor and each of the crates is 0.700. What is the magnitude F32 of the force on crate 3 from crate 2? Number Units IN the tolerance is +/-2% Click if you would like to Show Work for this question: Open Show Work Question Attempts: Unlimited SAVE FOR LATER SUBMIT ANSWER 10:46 PM to search ENG 4/4/2021 13) pri sc pause (brea delte 17 insert %23 3 4 5. backspac RConsider the figure shown in the following figure. You are loweringtwo boxes, one on top of the other, down a ramp by pulling on a ropeparallel to the surface of the ramp. Both blocks move with constantvelocity of 10.0 [m/s]. The coefficient of kinetic friction between theramp and the lower box is 0.555 and the coefficient of static frictionbetween the two boxes is 0.750. A. Draw the Free-Body diagram of both blocks. Set the ?-axis parallel to the ramp. B. Write Newton’s 2nd law along the ? and ? directions for both blocks considering their state of motion (accelerations). C. What are the magnitude and direction of the frictional force on the upper box? D. What is the magnitude of the applied force? E. Determine the angle at which the top block will start to slide down the bottom block.
- Consider the figure shown in the following figure. You are loweringtwo boxes, one on top of the other, down a ramp by pulling on a ropeparallel to the surface of the ramp. Both blocks move with constantvelocity of 10.0 [m/s]. The coefficient of kinetic friction between theramp and the lower box is 0.555 and the coefficient of static frictionbetween the two boxes is 0.750. A. Draw the Free-Body diagram of both blocks. Set the ?-axis parallel to the ramp. B. Write Newton’s 2nd law along the ? and ? directions for both blocks considering their state ofmotion (accelerations). C. What are the magnitude and direction of the frictional force on the upper box? D. What is the magnitude of the applied force? E. Determine the angle at which the top block will start to slide down the bottom block.Chapter 05, Problem 010 GO A 0.180 kg particle moves along an x axis according to x(t) = - 14.0 + 2.00 t + 4.00 2- 5.00 t, with x in meters and t in seconds. In unit-vector notation, what is the net force acting on the particle at t = 3.30 s ? Give an expression for the (a) x, (b) y and (c) z components. (a) Number Units (b) Number Units (c) Number Units Click if you would like to Show Work for this question: Open Show Work Question Attempts: Unlimited SAVE FOR LATER SUBMIT ANSWER powered by MapleNet ere to search 1:51 PM ENG 4/4/2021 ASUS 19home prt sc pause break delete f10 end f1Pgup f12Pgdn insert & 21 4. 8 backspo-Gmail 4:19 PM bartleby.com 2. An athlete slides down from rest 40.0 meter along an icy hill which is 35 degrees from the horizontal. He then continues sliding on the level ice. a) If the coefficient of kinetic friction between the athlete and ice is 0.20 (neglect air resistance) find speed (m/s) of athlete at the foot of the plane. b) ) find the distance (m) from the foot of the plane to the point where he has landed to the level ice
- You are pushing a box, apply Fa = 90 N. The box's mass is 25 kg. The coefficients of friction are μs =0.60 and μk = 0.4. The box was stationary when you began pushing. Calculate the frictional force magnitude exerted on the box by the floorof air Question 10. A 16.2-kg sled is being pulled across a horizontal surface at a constant velocity. The pulling force has a magnitude of 65.1 N and is directed at an angle of 30° above the horizontal. Determine the coefficient of kinetic friction. Ans: 0.446 Question 11. A person in tuiA block of mass 5.40 kg is pushed up against a wall by a force P that makes an angle of = 50.0° angle with the horizontal as shown below. The coefficient of static friction between the block and the wall is 0.300. (a) Determine the possible values for the magnitude of P that allow the block to remain stationary. (If there is no maximum, enter NONE in that answer blank.) P. maxl= IP A N X Your response differs from the correct answer by more than 10%. Double check your calculations. N P Pminh, = 92.32 (b) What happens if IP has a larger value than IP The block slides up the wall. The block does not slide along the wall. The block slides down the wall. |Pmaxl = P min! = What happens if IP has a smaller value than IP min!? The block slides up the wall. O The block does not slide along the wall. The block slides down the wall. (c) Repeat parts (a) and (b) assuming the force makes an angle of = 12.0° with the horizontal. Determine the possible values for the magnitude of P that allow the…
- A block of mass 20kg is pushed against a vertical wall by force P. The coefficient of friction between the surface and the block is 0.2. If theta = 30 degrees, what is the minimum magnitude of P to hold the block still?I understand that in order for the block to sit motionless, the net forces acting on the block must be zero. I set my equation to be Net Force = 0 = Psin(theta) + Force Friction - Force Gravity.Which I rearranged as P = (Force Gravity - Force Friction)/sin(theta) or P = (mg-μ(mg))/sin(theta)Doing this gives me a value of 313.6N rather than 202.9N which I should be getting. What am I doing wrong?Consider the figure shown in the following figure. You are lowering two boxes, one on top of the other, down a ramp by pulling on a rope parallel to the surface of the ramp. Both blocks move with constant velocity of 10.0 [m/s]. The coefficient of kinetic friction between the ramp and the lower box is 0.555 and the coefficient of static friction between the two boxes is 0.750.1. Write Newton's 2nd law of motion along the x and y directions for both blocks considering their state of motion.2. What are the magnitude and direction of the firctional force on the upper box?3. Draw the free-body diagram of both blocks. Set the x-axis parallel to the ramp.Hi, I have to on a graph vectors that illustrate this problem. Suppose you have to move a heavy crate of weight 875 N by sliding it along a horizontal concrete floor. You push the crate to the right with a horizontal force of magnitude 300 N, but friction prevents the crate from sliding. I have tried to have the forces in the right direction. Normal force is vertically up, weight is down, friction force is in the opposite direction to force. But I'm still not getting the graph right. Not sure if the lengths of the forces have something to do with it.