The figure shows an overhead view of a 0.025 kg lemon half and two of the three horizontal forces that act on it as it is on a frictionless table. Force F→1 has a magnitude of 3 N and is at θ1 = 29˚. Force F→2 has a magnitude of 8 N and is at θ2 = 27˚. In unit-vector notation, what is the third force if the lemon half (a) is stationary, (b) has the constant velocity v→=(11î −16ĵ ) m/s, and (c) has the v→=(11tî −11tĵ ) m/s2, where t is time?
The figure shows an overhead view of a 0.025 kg lemon half and two of the three horizontal forces that act on it as it is on a frictionless table. Force F→1 has a magnitude of 3 N and is at θ1 = 29˚. Force F→2 has a magnitude of 8 N and is at θ2 = 27˚. In unit-vector notation, what is the third force if the lemon half (a) is stationary, (b) has the constant velocity v→=(11î −16ĵ ) m/s, and (c) has the v→=(11tî −11tĵ ) m/s2, where t is time?
Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter10: Rotational Motion
Section: Chapter Questions
Problem 80P
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The figure shows an overhead view of a 0.025 kg lemon half and two of the three horizontal forces that act on it as it is on a frictionless table. Force F→1 has a magnitude of 3 N and is at θ1 = 29˚. Force F→2 has a magnitude of 8 N and is at θ2 = 27˚. In unit-vector notation, what is the third force if the lemon half (a) is stationary, (b) has the constant velocity v→=(11î −16ĵ ) m/s, and (c) has the v→=(11tî −11tĵ ) m/s2, where t is time?
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VIEWStep 2: Forces on the lemon half
VIEWStep 3: Part (a): Calculating third force if lemon half is stationary
VIEWStep 4: Part(b): calculating third force if has the constant velocity
VIEWStep 5: Part(c): calculating third force if the lemon half has the velocity 11tî −11tĵ m/s
VIEWStep 6: Conclusion
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