In the fig. shown, compute the following : (1-2) the resultant, R 50 lb 6 in.- R = 40 lb A B 20 lb C (3) What is the angle of the Resultant with 6 in. Respect to the x- axis measured CW F - 6 in.- (4-6) how far from point C will the line of action of the R bisect the edge ABC? X = 50 lb

Find the viscosity of Water @ 25oC and @37oC

The differential change in pressure p close to the surface of a static fluid is given by the following expression:dp/dy = -3Ap2,where A is a constant, with units of 1/(atm•m), and p is the pressure in atm. The pressure at the surface of the fluid is p(0) = 1 atm, and the coordinate y here is positive upwards with origin at the surface.  An absulute pressure gauge is placed at a depth 0.19m in the fluid. What would be the reading of the pressure gauge in units in atm? you can take the constant A=1(atm.m)^-1

The figure below (for illustrative purposes) shows a perfectly rigid (non-deformable) beam which is perfectly rigidly supported at points P and R by two force measurement scales, 1 and 2. PQ is 65 cm and PR is 150 cm. The beam is horizontal when each of scales 1 and 2 gives a reading of zero. Acceleration due to gravity is 9.81 ms-2. Scale 1 Point P Point Q Point R Scale 2 Choose one of the following options that will give the correct readings of scales 1 and 2 when a mass of 30 kg acts vertically downwards at point Q. (The scales are not loaded to you will have to calculate the answer) O A Reading of Scale 1 = 150 kg; Reading of scale 2 = 65 kg O B. Reading of Scale 1 = 166.77 kg; Reading of scale 2 = 127.53 kg O C. Reading of Scale 1 = 150 Newton; Reading of scale 2 = 65 kg O D. Reading of Scale 1 = 166.77 Newton; Reading of scale 2 = 127.53 Newton