In the fig. shown below we can find the lower critical frequency due to thebypass RC circuit is equal to . . the output RC circuit is equal tothe input Rc circuit is equal to .Assume re = 9.6 Q and B = 200andVoe+15 VR,R.033 F0.1 F706ENT600 150 mV多木るFCL(in)= 282 Hz FCL(out)=53HZ FCL(bypass)=36 HzFCL(in)= 282 Hz FCL(out)=51HZ FCL(bypass)=36 HzFCL(in)= 282 Hz FCL(out)=51HZ FCL(bypass)=30 HzFCL(in)= 242 Hz FCL(out)=51HZ FCL(bypass)=36 HzNo option is correct

Answered: Image /qna-images/answer/584a4673-e3ca-47e8-91e0-49f0543620c3.jpg

In the fig. shown below we can find the lower critical frequency due to the bypass RC circuit is equal to . the output RC circuit is equal to . and the input Rc circuit is equal to .Assume re = 9.6 Q and B = 200 Vo +15 V Re 390 R, 68 kl 033 F 2N3904 0.1 F 600 1 REI 33 1 50 mV 22 kl 15 k FCL(in)= 282 Hz FCL(out)=53HZ FCL(bypass)=36 Hz FCL(in)= 282 Hz FCL(out)=51HZ FCL(bypass)=36 Hz FCL(in)= 282 Hz FCL(out)=51HZ FCL(bypass)=D30 Hz FCL(in)= 242 Hz FCL(out)=51HZ FCL(bypass)=D36 Hz O No option is correct • W

In the fig. shown below we can find the lower critical frequency due to the bypass RC circuit is equal to . the output RC circuit is equal to . and the input Rc circuit is equal to .Assume re = 9.6 Q and B = 200 Vo +15 V Re 390 R, 68 kl 033 F 2N3904 0.1 F 600 1 REI 33 1 50 mV 22 kl 15 k FCL(in)= 282 Hz FCL(out)=53HZ FCL(bypass)=36 Hz FCL(in)= 282 Hz FCL(out)=51HZ FCL(bypass)=36 Hz FCL(in)= 282 Hz FCL(out)=51HZ FCL(bypass)=D30 Hz FCL(in)= 242 Hz FCL(out)=51HZ FCL(bypass)=D36 Hz O No option is correct • W

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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