Amplifier's Frequency Response Vcc=20V R1 = 40 kohm R2 = 10 kohm Rc = 4 kohm RE=2 kohm Rs = 1 kohm RL = 2.2 kohm Cs=10 uF Cc = 1 uF CE=20 uF Cbc = 4 pF Cbe = 36 pF Cce 1 pF Cwi=6 pF Cwo=8 pF Cs Beta = 100 Rs + V₂ + V₁ R₁ a. b. C. Vcc R₂ Cw₁ Cbc Rc C be RE 47. Calculate the saturation current, IC(sat) 3.33 MA 4.26 mA 5.3 mA Cc Cce CE CWo

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AMPLIFIER'S FREQUENCY RESPONSE 10

Amplifier's Frequency Response
Vcc=20V
R1 = 40 kohm
R2 = 10 kohm
Rc = 4 kohm
RE=2 kohm
Rs = 1 kohm
RL = 2.2 kohm
Cs = 10 uF
Cc = 1 uF
CE=20 uF
Cbc = 4 pF
Cbe = 36 pF
Cce 1 pF
Cwi=6 pF
Cwo = 8 pF
Beta = 100
+=1
Rs
V₂
2
Cs
+
V₁
a.
b.
R₁
C.
d.
Vcc
R₂ Cw₁
Cbc
Rc
Che
47. Calculate the saturation current, IC(sat)
3.33 MA
4.26 MA
5.3 mA
1.67 mA
RE
Cc
Cce
CE
Cwo
:
RL
Transcribed Image Text:Amplifier's Frequency Response Vcc=20V R1 = 40 kohm R2 = 10 kohm Rc = 4 kohm RE=2 kohm Rs = 1 kohm RL = 2.2 kohm Cs = 10 uF Cc = 1 uF CE=20 uF Cbc = 4 pF Cbe = 36 pF Cce 1 pF Cwi=6 pF Cwo = 8 pF Beta = 100 +=1 Rs V₂ 2 Cs + V₁ a. b. R₁ C. d. Vcc R₂ Cw₁ Cbc Rc Che 47. Calculate the saturation current, IC(sat) 3.33 MA 4.26 MA 5.3 mA 1.67 mA RE Cc Cce CE Cwo : RL
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