Biochemistry
9th Edition
ISBN: 9781319114671
Author: Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher: W. H. Freeman
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Introns are non-coding sequences and exons are coding sequences in the gene. Splicing is the process of removal of introns from the gene and joining of exons to produce a mature mRNA. The mature mRNA undergoes translation process to synthesize proteins.
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- There may be positive selection on introns if they are adapted to retaining specific stem-loop structures. Such an adaptation is called itsarrow_forwardWhat is the orientation of this gene relative to contig1? How do you know? Where are the start codon and the stop codon give the base position numbers (coordinates) of the start and the stop codon)?arrow_forwardUsing a computer algorithm that searches for sequence similarities in other organisms, you discover that hexose kinase is a highly conserved gene that is expressed by many species, both prokaryotic and eukaryotic. The most closely related prokaryotic homolog of hexose kinase has a protein sequence in which 90% of the amino acids are identical to those of the human version of the gene. To learn more about their similarity at the DNA level, you obtain segments of the genomic DNA coding for the hexose kinase gene in both humans and this prokaryotic species. After combining both DNA samples, you heat them to denature the DNA strands and then allow them to cool and reanneal. Finally, you examine the DNA hybrids you obtain under the electron microscope. Practice Question 3 A) Your analysis reveals that there are three different DNA hybrids in this sample, these can be seen below. You reason that one must belong to the prokaryotic species, one to the humans and the third arose when one strand…arrow_forward
- A certain amber suppressor inserts glutamine in response to the amber codon. What is the most likely change in the anticodon of a tRNAGln that created this suppressor strain?arrow_forwardA common feature of many eukaryotic mRNAs is the presence of a rather long 3′ UTR, which often contains consensus sequences. Creatine kinase B (CK-B) is an important enzyme in cellular metabolism. Certain cells—termed U937D cells—have lots of CK-B mRNA, but no CK-B enzyme is present. In these cells, the 5′ end of the CK-B mRNA is bound to ribosomes, but the mRNA is apparently not translated. Something inhibits the translation of the CK-B mRNA in these cells. Researchers introduced numerous short segments of RNA containing only 3′ UTR sequences into U937D cells. As a result, the U937D cells began to synthesize the CK-B enzyme, but the total amount of CK-B mRNA did not increase. The introduction of short segments of other RNA sequences did not stimulate the synthesis of CK-B; only the 3′ UTR sequences turned on the translation of the enzyme. On the basis of these results, propose a mechanism for the inhibition of CK-B translation in the U937D cells. Explain how the introduction of short…arrow_forwardWhich of the following mutations in the protein-coding region of a gene is more likely to lead to complete loss of function of the encoded protein: an insertion of six nucleotides or a deletion of two nucleotides? Briefly explain your answer.arrow_forward
- Using the transcription unit diagrammed below, in which exons are represented by blue boxes and introns are represented by the connecting lines. You discover a single base deletion in region E of this DNA sequence. Regarding transcription, this mutation will likely: 1.) Result in an alteration to the mRNA sequence. 2.)Have no effect on transcription or the mRNA sequence 3.)Prevent transcription at the TATAA box 4.) Result in an increase or decrease in the amount of mRNA transcribedarrow_forwardAs we have learned in this chapter, the Nanos protein inhibits the translation of hunchback mRNA, lowering the concentration of Hunchback protein at the posterior end of a fruit-fly embryo and stimulating the differentiation of posterior characteristics. The results of experiments have demonstrated that the action of Nanos on hunchback mRNA depends on the presence of an 11-base sequence that is located in the 3′ untranslated region (3′ UTR) of hunchback mRNA. This sequence has been termed the Nanos response element (NRE). There are two copies of NRE in the 3′ UTR of hunchback mRNA. If a copy of NRE is added to the 3′ UTR of another mRNA produced by a different gene, that mRNA is repressed by Nanos. The repression is greater if several NREs are added. On the basis of these observations, propose a mechanism for how Nanos inhibits Hunchback translation.arrow_forward
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