In the context of a sewer system, your objective is to find the optimal slope (SS) of a pipe to meet a design flow rate (QdQd) and a maximum allowed flow depth percentage (y/Dy/D). Utilize the flow velocity equation: V = -2 * SQRT(8 * g * R * S) * LOG10((ks / (14.8 * R)) + (2.51 * μ / (4 * ρ * R * SQRT(8 * g * R * S))) Given: Design flow rate (QdQd): 4.12 m³/s Pipe diameter (DD): 1 m Pipe roughness (ksks): 1.50E-06 m Maximum flow depth percentage (y/Dy/D): 85% Fluid density (ρρ): 999.1 kg/m³ Fluid viscosity (μμ): 1.14E-03 Pa·s Acceleration due to gravity (gg): 9.81 m/s²
In the context of a sewer system, your objective is to find the optimal slope (SS) of a pipe to meet a design flow rate (QdQd) and a maximum allowed flow depth percentage (y/Dy/D). Utilize the flow velocity equation: V = -2 * SQRT(8 * g * R * S) * LOG10((ks / (14.8 * R)) + (2.51 * μ / (4 * ρ * R * SQRT(8 * g * R * S))) Given: Design flow rate (QdQd): 4.12 m³/s Pipe diameter (DD): 1 m Pipe roughness (ksks): 1.50E-06 m Maximum flow depth percentage (y/Dy/D): 85% Fluid density (ρρ): 999.1 kg/m³ Fluid viscosity (μμ): 1.14E-03 Pa·s Acceleration due to gravity (gg): 9.81 m/s²
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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In the context of a sewer system, your objective is to find the optimal slope (SS) of a pipe to meet a design flow rate (QdQd) and a maximum allowed flow depth percentage (y/Dy/D). Utilize the flow velocity equation: V = -2 * SQRT(8 * g * R * S) * LOG10((ks / (14.8 * R)) + (2.51 * μ / (4 * ρ * R * SQRT(8 * g * R * S)))
Given:
- Design flow rate (QdQd): 4.12 m³/s
- Pipe diameter (DD): 1 m
- Pipe roughness (ksks): 1.50E-06 m
- Maximum flow depth percentage (y/Dy/D): 85%
- Fluid density (ρρ): 999.1 kg/m³
- Fluid viscosity (μμ): 1.14E-03 Pa·s
- Acceleration due to gravity (gg): 9.81 m/s²
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