In the circuit shown, the values of the resistors are R1=10Ω, R2=20Ω, R3=30Ω and R4=40Ω. The current through R3is 0.200 A. Find the voltage supplied by the battery, Vbat.

Consider the circuit shown in the figure below, where R, = 8.00 N, R, = 9.00 N, and Ɛ = 7.00 V. 10.0 N R2 5.00 N 2.00 N (a) Find the voltage (in V) across R,. 1' V (b) Find the current (in A) in R,. A

The drawing shows three different resistors in two different circuits. The battery has a voltage of V = 28 V, and the resistors have resistances of R₁-50.00, R₂-25.002 and R3-10.00. Determine the current through and the voltage across each resistor. R₁ (a) ½₁ = i 12-i √3 = i V₁ = i V2= i V3-i R₁ R₂ R3 R₂ R3 (b) (a)

Problem 5: A current of I- 2.6 A passes through the circuit shown, where R- 65 3R 5R V) 2R 6R 2R 7R 5R 10R Otheexpertta.com Part (a) In terms of R, I, and numeric values, write an expression for the voltage of the · source, V. Part (b) What is the voltage, V in volts? tan( sin() cotanO a acos cosh0t cosO asin() acotan 4 5 6 sinh() cotanhO *1 23 0 tanh0c O Degrees O Radians CLEAR BACKSPACE

In the circuit shown, the potential difference VA = VB = 46.0 V and the resistance R1 = R2 = R3 = R4 = 155 Ohms. The arrows for currents IA and IB indicate the direction of positive current flow. The arrows do not necessarily indicate the direction that the current flows.  Find IA Find IB

The circuit below contains two real batteries, each having significant internal resistance. Battery #1 has an EMF of 6.00 V and an internal resistance of 1.00 ohm. Battery #2 has an EMF of 12.00 V and an internal resistance of 2.00 ohms. These two batteries are connected in series with two resistors R, = 6.00 ohms and R,= 3.00 ohms. ri d (6.00,V) (1.00 0) R1 (6.00 N) R2 (3.00 N) a r2 E2 (2.00 Q) (12.00 V) 18. The current in the 12.00 Volt battery is equal to C. 0.500 A. A. 0.750 A. B. 1.00 A. D. 2.00 A. E. 1.50 A. 19. The potential difference across the terminals of battery #1 from point C to point d is equal to C. 7.00 V. A. 5.50 V. B. 6.00 V. D. 5.00 V. E. 6.50 V. 20. The potential difference across the terminals of battery #2 from point a to point b is equal to C. 13.00 V. A. 14.00 V. В. 10.00 V. D. 11.0 V. E. 12.00 V.

F₁ = L1, B₂ чт вът Різі чом =1032 V R -Gv 100 qüdrh I 1 R2 R23 2. Four resistors and a 6.0-V battery are arranged as shown in the circuit diagram. Find the equivalent resistance of the circuit b. Find the current through the 10-Ohm resistor a. sonsufit c. Find the power delivered to the 10-Ohm resistor R₁-4092 -18V -18V 13 C+ D B=6V 6VI Azov I=I1 + 0.64 AQUOS to 218-12 = 30 I H = -1 R4-2002 14. 0.64 1₂V R₂-3002 -IA F 12V E R3=1092 holong s vivang to 6 DS sailwaqogani THOS T20 3. A horizontal wire of length 6.0m carries a current of 6.0A and is oriented so that Forth's magnetic field is due north at this

In the figure the current in resistance 6 is i6 = 1.31 A and the resistances are R₁ = R₂ = R3 = 1.5202, R4 = 15.00, R5 = 8.490, and R6 = 3.41 Q. What is the emf of the ideal battery? Number R₁ Units R3 www R₂ www R₁ www R₂ 16 R6