In the circuit shown in the figure . the 6.0 N resistor is consuming energy at a rate of 21.0 J/s when the current through it flows as shown. 20.0 1 170 E = ? 190 >6.0 2 20.0 1 25 V 3.0N 13 N 1.00 Part A Find the current through the ammeter A. ANSWER: I = A Part B What are the polarity and emf of the battery E, assuming it has negligible internal resistance? ANSWER: E = V

Physics for Scientists and Engineers, Technology Update (No access codes included)
9th Edition
ISBN:9781305116399
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter28: Direct-current Circuits
Section: Chapter Questions
Problem 28.55AP: For the circuit shown in Figure P28.55. the ideal voltmeter reads 6.00 V and the ideal ammeter reads...
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Please answer part A and part B. 

In the circuit shown in the figure . the 6.0 N resistor is consuming energy at a rate of 21.0 J/s when the current through it flows as shown.
20.0 1
170
E = ?
190
>6.0 2
20.0 1
25 V
3.0N
13 N
1.00
Part A
Find the current through the ammeter A.
ANSWER:
I =
A
Part B
What are the polarity and emf of the battery E, assuming it has negligible internal resistance?
ANSWER:
E =
V
Transcribed Image Text:In the circuit shown in the figure . the 6.0 N resistor is consuming energy at a rate of 21.0 J/s when the current through it flows as shown. 20.0 1 170 E = ? 190 >6.0 2 20.0 1 25 V 3.0N 13 N 1.00 Part A Find the current through the ammeter A. ANSWER: I = A Part B What are the polarity and emf of the battery E, assuming it has negligible internal resistance? ANSWER: E = V
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