MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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- The average age for licensed drivers in a county is µ = 41.6, σ = 12, and the distribution is approximately normal. A county police officer was interested in whether the average age of drivers receiving speeding tickets differed from the average age of the driving population. She obtained a sample of N = 16 drivers with speeding tickets. The average age for this sample was M = 34.4 and alpha = 0.05. calculate statistical power for this study.arrow_forward3. You want to determine the effectiveness of a novel cancer therapy, RS7, in treating lung cancer. You cultured lung cancer microtissues in cell culture plates with equal numbers of cells per well. You exposed plate 1 to the novel drug and left plate 2 untreated (control). You analyzed both plates using flow cytometry and propidium iodide to identify live and dead cells. The results below represent the number of viable cells. Using a t-test, determine whether RS7 reduces the viability of lung cancer cells. Plate 1 (RS7): X1 = 65,434 X2 = 70,250 Plate 2 (control): X'1 = 80,760 X'2 = 78,562 X3= 63,962 X'3=81,435 A) State the null hypothesis (Ho): X4= 61,030 X'4 = 75,650 X5= 60,572 X'5 = 77,112arrow_forwardConsider a simple linear regression model, Y₁ = Bo + B₁X₁ + ₁ for i=1,2,...,n with the usual random error term (&) assumptions. Suppose that hypotheses Ho: P₁ = 0 against H₁:₁ <0 were tested and Ho: B₁ = 0 was rejected. Assume ₁e₁² = 0. ei i) Briefly explain what the conclusion of the test means for the values of Y given the values of X. -1 ii) Draw an example of a scatter plot with the fitted regression line for the problem mentioned above. iii) Calculate and interpret the correlation coefficient for the problem at hand.arrow_forward
- In North America, between 100 million and 1 billion birds die each year by crashing into windows on buildings, more than any other human-related cause. This figure represents up to 5% of all birds in the area. One possible solution is to construct windows angled downward slightly, so that they reflect the ground rather than an image of the sky to a flying bird. An experiment by Klem et al. (2004) compared the number of birds that died as a result of vertical windows, windows angled 20 degrees off vertical, and windows angled 40 degrees off vertical. The angles were randomly assigned with equal probability to six windows and changed daily; assume for this exercise that windows and window locations were identical in every respect except angle. Over the course of the experiment, 30 birds were killed by windows in the vertical orientation, 15 were killed by windows set at 20 degrees off vertical, and 8 were killed by windows set at 40 degrees off vertical. . Clearly state an appropriate…arrow_forwardThe data in worksheet 2.2 have spec limits USL/LSL = 40 ± 1. Perform the process capability analysis (Cp, Cpk, Pp, and Ppk) and diagnose the process, i.e. what problems are present? What steps should be taken to improve the process and how effective will they be?arrow_forwardAviation and high-altitude physiology is a specialty in the study of medicine. Let x = partial pressure of oxygen in the alveoli (air cells in the lungs) when breathing naturally available air. Let y = partial pressure when breathing pure oxygen. The (x, y) data pairs correspond to elevations from 10,000 feet to 30,000 feet in 5000 foot intervals for a random sample of volunteers. Although the medical data were collected using airplanes, they apply equally well to Mt. Everest climbers (summit 29,028 feet). (units: mm Hg/10) (units: mm Hg/10) 6.5 5.4 4.2 3.3 2.1 y 43.6 32.3 26.2 16.2 13.9 Ex = 21.5, Ey = 132.2, Ex² = 104.35, Ey2 = 4086.34, Exy = 650.51, and r= 0.978. %3D Ex 21.5 Ey 132.2 Ex2 104.35 Ey2|4086.34 Exy 650.51 r 0.978 Use a 1% level of significance to test the claim that p > 0. (Use 2 decimal places.) critical t Verify that S. - 2.9006, a = -3.208, and b = 6.895. e Se a b Find the predicted pressure when breathing pure oxygen if the pressure from breathing available air is x…arrow_forward
- 9) Find L3.2 (5) using the nodes xo = 3,x1 = 4, x2 = 6 ,x3 = 8 %3Darrow_forwardA manufacturer is evaluating the variation in thickness for piezoelectric actuators from two component suppliers. The two populations are independent, and the thickness measurements are normally distributed. The thickness was measured for a sample of 30 products purchased from Supplier 1, and it was found that = 3.8048 . A sample of 30 products was also purchased from Supplier 2 and it was found that 5.2967. S1 S2 Is there evidence at the 0.1 level of significance that the thickness variance for Supplier 1 is smaller than for Supplier 2? (Round answers to 3 decimal places as needed) The correct alternative hypothesis is: O H1:0 + 0 OH1: H1 > µ2 : O H1:0} < o? O H1:0 2 0 O H1:0 O H1: µ1 2 l2 O H1: 41 < µ2 The test statistic is Fobs The probability of variance ratios at or beyond Fobs occurring by chance is = The decision is to Select an answer v that the variance in The correct summary would be: Select an answer thickness for Supplier 1 is smaller than Supplier 2.arrow_forwardAviation and high-altitude physiology is a specialty in the study of medicine. Let x = partial pressure of oxygen in the alveoli (air cells in the lungs) when breathing naturally available air. Let y = partial pressure when breathing pure oxygen. The (x, y) data pairs correspond to elevations from 10,000 feet to 30,000 feet in 5000 foot intervals for a random sample of volunteers. Although the medical data were collected using airplanes, they apply equally well to Mt. %3D Everest climbers (summit 29,028 feet). (units: mm Hg/10) (units: mm Hg/10) 7.3 4.6 4.2 3.3 2.1 42.4 31.7 26.2 16.2 13.9 (a) Verify that Ex = 21.5, Ey = 130.4, Ex = 107.39, Ey = 3944.74, Exy = 648.03, andr 0.969. Σχ 21.5 %3D %3D Ey 130.4 Ex2 | 107.39 Ey2 3944.74 Exy 648.03 r0.9686 (b) Use a 10% level of significance to test the claim that p > 0. (Use 2 decimal places.) t 6.79 critical t 1.6377 Conclusion Reject the null hypothesis, there is sufficient evidence that p > 0. Reject the null hypothesis, there is…arrow_forward
- A number of studies have shown lichens (certain plants composed of an alga and a fungus) to be excellent bio-indicators of air pollution. An article gives the following data (n = 13) on x = NO3- wet deposition (g N/m²) and y = lichen (% dry weight): x 0.05 0.10 0.11 0.12 0.31 0.37 0.42 0.58 0.68 0.68 0.73 0.85 0.92 y 0.53 0.58 0.45 0.54 0.57 0.53 1.03 0.89 0.90 1.02 0.91 1.00 1.66 Predictor Constant no3 depo Estimate 0.39329 0.9286 0.1767 S = 0.1866 R-sq = 71.5% Standard Error 0.09566 t Stat 4.11 5.26 p-value 0.002 0.000 R-sq (adj) = 68.9% (a) What are the least square estimates of B and ẞ₁? (Round your answers to three decimal places.) bo = = (b) What is the margin of error for a 95% CI for ẞ₁? (Round your answer to four decimal places.) Margin of Error = (c) Predict lichen N for an NO3 - deposition value of 0.7. (Round your answer to three decimal places.) % dry weight (d) What is the estimate of σ? (Round your answer to four decimal places.) S = % dry weightarrow_forwardAviation and high-altitude physiology is a specialty in the study of medicine. Let x = partial pressure of oxygen in the alveoli (air cells in the lungs) when breathing naturally available air. Let y = partial pressure when breathing pure oxygen. The (x, y) data pairs correspond to elevations from 10,000 feet to 30,000 feet in 5000 foot intervals for a random sample of volunteers. Although the medical data were collected using airplanes, they apply equally well to Mt. Everest climbers (summit 29,028 feet). (units: mm Hg/10) (units: mm Hg/10) 3.3 x 6.7 Ly 42.2 4.9 4.2 2.1 31.7 26.2 16.2 13.9 (a) Verify that Ex = 21.2, Ey = 130.2, Ex? = 101.84, Ey? = 3927.82, Exy = 630.76, and r= 0.982. Ir = Ex 21.2 Ey 130.2 Ex2 101.84 Ey2 3927.82 Exy 630.76 r 0.982 (b) Use a 10% level of significance to test the claim that p > 0. (Use 2 decimal places.) t 9.01 critical t 1.64 Conclusion O Reject the null hypothesis, there is sufficient evidence thatp >0. O Reject the null hypothesis, there is…arrow_forward
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