In order to test the null hypothesis, the t calculated is equal to: O 3.895 O 3.878 O 3.932 O 3.914

An advertising firm has decided to ask 115 customers at each of four local shopping malls if they are willing to take part in a market research survey. At . = 0.05 is there evidence to show that the proportions are not all the same. A B D Willing 62 67 69 70 Not Willing 53 48 46 45 What are the expected numbers? (round to 3 decimal places) D Willing Not Willing The hypotheses are Ho : PA = pPB = Pc = Pp HA: At least one of the proportions is different. (claim) Since a = 0.05 the critical value is 7.815 The test value is: (round to 3 decimal places) The p-value is (round to 3 decimal places) So the decision is to do not reject Họ reject H, Thus the final conclusion is There is enough evidence to reject the claim that at least one of the proportions is different. There is enough evidence to support the claim that at least one of the proportions is different. There is not enough evidence to support the claim that at least one of the proportions is different. OThere is not enough evidence…

Dysart's is interested in whether the average check size is more or less than before the pandemic, when the average per check was $14. Select the v 14 [ Select ] correct symbols to use in the alternate hypothesis for this hypothesis test. Ha: [ Select ]

For the following hypothesis test: HO: m ≤ 14 HA: m >14 a: 0.01 with n = 38, o = 9, and x = 16, which of the following is TRUE? Select one: a. reject null hypothesis and conclude that the mean is equal to or less than 14 O b. fail to reject null hypothesis and conclude that the mean is equal to or less than 14 c. reject null hypothesis and conclude that the mean is greater than 14 d. fail to reject null hypothesis and conclude that the is greater than 14

A student wishes to see if at her work place the proportion females who do not have children is less than the proportion of males who do not have children. To test her claim she randomly selects 358 females 60 did not have children. She then randomly selects 322 males workers and out of them 59 did not have children. Test her claim at œ=0.05 to see if she was right. The correct hypotheses are: О Но: рr рм(claim) Ο H: pF PM НА: PF < рм (claim) O Ho:PF На: рr + рм (claim) = PM Since the level of significance is 0.10 the critical value is -1.282 The test statistic is: (round to 3 places) The p-value is: (round to 3 places) The decision can be made to: O reject Ho O do not reject Ho

C. Test the hypotheses Но: ß0 0 versus Ha: ß04 0. d. Determine the p-value of the test of Ho: Po 0 Noltems 1 1 1 1 22 22 233 33 Time 4.8 14.7 13.7 9.5 2.4 11.8 10.5 12.0 14.3 16.4 17.9 14.5 16.7 20.1 16.8 Noltems 3 3 3 3 3 44 4 44 5 Time 20.8 26.8 12.9 13.0 15.4 10.8 20.3 22.3 20.0 21.9 20.7 20.9 19.9 17.1 19.1 Noltems 5 5 5 5 6 6 6 6 6 6 6 777 7 Time17.2 18.1 17.9 12.9 19.6 27.9 22.2 23.2 17.5 15.3 21.8 17.9 20.1 18.9 29.3 Noltems 7 8 8 8 8 8 89 9 9 9 9 10 10 10 Time21.5 26.5 28.2 25.1 26.1 28.2 22.3 21.8 25.5 24.4 18.1 26.7 24.6 30.1 21.5 Noltems 10 10 10 11 1 12 12 12 12 14 14 15 16 Time25.2 28.2 22.6 31.3 27.2 28.8 29.7 34.3 27.9 29.7 28.7 34.6 38.0 28.0 37.0 Noltems 17 18 18 18 19 20 21 22 23 2425 25 25 26 27 Time32.5 39.5 39.0 37.0 35.5 38.3 44.0 39.6 42.3 34.6 44.9 47.4 49.2 45.8 44.0 Noltems 27 30 30 31 37 39 40 41 45 46 Time46.1 42.9 48.3 46.0 48.2 54.749.955.4 57.1 52.4