In one of the classic nuclear physics experiments at the beginning of the 20th century, alpha particles were accelerated toward stationary gold nuclei. Some alpha particles were reflected straight back due to the Coulomb interaction between the alpha particle and the nucleus. If the kinetic energy of a doubly charged alpha nucleus was 9.41 MeV when it was a large distance away from the nucleus, how close to the gold nucleus (79 protons) could it come before being reflected? Enter this distance in units of fm = 10-15 m. 1 MeV = 1.6*10-13 J Enter a number with one digit behind the decimal point.

What potential difference is needed to give a helium nucleus (Q=2e)(Q=2e) 75.0 keV of kinetic energy?

In one of the classic nuclear physics experiments at the beginning of the 20th century, an alpha particle was accelerated toward a gold nucleus, and its path was substantially deflected by the Coulomb interaction. If the energy of the doubly charged alpha nucleus was 7.80 MeV, how close (in m) to the gold nucleus (79 protons) could it come before being deflected?

MY NOTES ASK YOUR TEACHER In one of the classic nuclear physics experiments at the beginning of the 20th century, an alpha particle was accelerated toward a gold nucleus, and its path was substantially deflected by the Coulomb interaction. If the energy of the doubly charged alpha nucleus was 2.87 MeV, how close (in m) to the gold nucleus (79 protons) could it come before being deflected? m DETULG

An Alpha particle ( a Helium nucleus with a +2e charge) enters a parallel plate arrangement through a hole in the positive plate held at +5.0V and is accelerated towards the negative plate held at -5.0V. a) What is speed of the Alpha particle when it reaches the negative plate? (Assume its initial velocity is zero) b) How fast is it moving when it is at the center of the gap between the plates? Mass of Alpha Particle: m = 6.645 × 10-27kg a Elementary charge: e = 1.602× 10-19C

A uranium nucleus fissions in two spherical fragments of charge 38e and 54e and radii 5.5-10-15 m and 6.2 10-15 m, respectively. Assume that the charge is distributed uniformly throughout the volumes, that just before separation each fragment is at rest, and that fragments surfaces are in contact. The electric potential energy of two spherical fragments in MeV (1 MeV = 1.6 10-13 J) is O 1.0 MeV. 220 MeV. 15 MeV. 250 MeV. 80 MeV.

Homework Question 13. A proton is shot at the nucleus of a gold atom. When the proton is a long way from the atom, its speed is 6 x106 m/sec. How far from the center of the nucleus is the turning point of the proton? (There is a periodic table in the appendix of your book.)

Cathode ray tubes (CRTs) used in old-style televisions have been replaced by modern LCD and LED screens. Part of the CRT included a set of accelerating plates separated by a distance of about 1.32 cm. If the potential difference across the plates was 24.0 kV, find the magnitude of the electric field (in V/m) in the region between the plates.

In a typical television or in an older computer monitor's cathode ray tube (CRT), electrons are accelerated from rest through a potential difference of 2.5×104 V, steered by magnetic fields, and finally strike particular spots on the screen at the front of the tube to create an image. What is the kinetic energy of the electrons after the accelerating process, as they are moving toward the screen?

A proton (m=1.67 x 10^-27 kg) travels a distance of 4.3 cm parallel to a uniform electric field 3.5 x 10^5 V/m between the plates shown in the figure. If the initial velocity is 3.2 x 10^5 m/s, find the magnitude of its final velocity in m/s. (Ignore gravity)