In Figure (a), both batteries have emf = 1.40 V and the external resistance R is a variable resistor. Figure (b) gives the electric potentials V between the terminals of each battery as functions of R: Curve 1 corresponds to battery 1, and curve 2 corresponds to battery 2. The horizontal scale is set by R$ = 0.400 Q2. What is the internal resistance of (a) battery 1 and (b) battery 2? 0.70-

3. The figure on the left below shows a schematic diagram of a battery. The voltage measured by U1 is called the terminal voltage given R1 = 1 ohm. In the figure on the right below, the terminal voltage of each of the battery-resistor combination is Vr = 1.5 volts. Find the following: a. The current passing through R5. b. The currents passing through R1 and R3 C. The voltage across R1. d. The voltage of the battery EMF. e. The percentage of voltage loss ot the battery due to the internal resistance R1. The power dissipated by the internal resistance R1. g. The power dissipated by R5 if R1 = R2 = R3 = R4 = 0. h. The percentage of power dissipation loss due to the four resistors R1, R2, R3, and R4 f. R1 R3 S10 R1 U1 1.500 EMF EMF R5 100 V1 R2 $10 EMF R4 EMF EMF

For the circuit below, determine the resistor voltage. The source is 5 volts, the Zener potential is 5.2 volts and the resistor is 1k ohms.

4. All batteries in the infinite chain shown in the figure have emf E and internal resistance r (see figure). Find the resultant emf and internal resistance across A and B