In executing the following code: MOV SI, 0300 START: MOV DI, 0302 ADD (DI), AX STOP: MOV AX, (SI) HLT with the following bytes contents: (0300H) = A9H, (0301H) = 4AH, (0302H) = 5BH, (0303H) = 6CH. The result will be: Select one: a. (0300H) = A9H, (0301H) = 4AH, (0302H) = 04H, (0303H) = B7H O b. (0300H) = 1AH, (0301H) = 2BH, (0302H) = 56H, (0303H) = 78H O c. (0300H) = 1AH, (0301H) = 2BH, (0302H) = 66H, (0303H) = 77H None of the options given here Od. O e. (0300H) = 1AH, (0301H) = 2BH, (0302H) = 3CH, (0303H) = 4DH

Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Question
In executing the following code:
MOV SI, 0300
START:
MOV DI, 0302
ADD (DI), AX
STOP:
MOV AX, (SI)
HLT
with the following bytes contents:
(0300H) = A9H, (0301H) = 4AH, (0302H) = 5BH, (0303H) = 6CH.
The result will be:
Select one:
O b.
a. (0300H) = A9H, (0301H) = 4AH, (0302H) = 04H, (0303H) = B7H
(0300H) = 1AH, (0301H) = 2BH, (0302H) = 56H, (0303H) = 78H
(0300H) = 1AH, (0301H) = 2BH, (0302H) = 66H, (0303H) = 77H
O c.
O d. None of the options given here
O e. (0300H) = 1AH, (0301H) = 2BH, (0302H) = 3CH, (0303H) = 4DH
Transcribed Image Text:In executing the following code: MOV SI, 0300 START: MOV DI, 0302 ADD (DI), AX STOP: MOV AX, (SI) HLT with the following bytes contents: (0300H) = A9H, (0301H) = 4AH, (0302H) = 5BH, (0303H) = 6CH. The result will be: Select one: O b. a. (0300H) = A9H, (0301H) = 4AH, (0302H) = 04H, (0303H) = B7H (0300H) = 1AH, (0301H) = 2BH, (0302H) = 56H, (0303H) = 78H (0300H) = 1AH, (0301H) = 2BH, (0302H) = 66H, (0303H) = 77H O c. O d. None of the options given here O e. (0300H) = 1AH, (0301H) = 2BH, (0302H) = 3CH, (0303H) = 4DH
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