In Drosophila melanogaster, wing shape is an autosomal trait. Vestigal wing is recessive (v) to the dominant trait for the normal long wings (V). In a mainland source population, the allele frequency of v is 0.02 . A small, experimental population of 100 flies was introduced on an island and had 20 flies with vestigal wings and 40 heterozygotes. What are the allele frequencies of V and v in this introduced population? What proportion (%) of heterozygotes and homozygous recessive flies would you expect to see after a few generations of mating on this island? What phenomenon of population genetics does this experiment demonstrate? p+q=l, p^2+ 2pq + q^2 = 1

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Extra Question Chapter 4 1. Consider the following cross concerning 4 different gene loci: AaBbCcDd (x) AabbCcdd From this cross, what is the probability of getting a progeny (offspring) with genotype AABbccdd? b. From this cross, what is the probability of getting a progeny (offspring) with genotype AabbCcDd? c. From this cross, what is the probability of getting a male progeny (offspring) with genotype aaBbCcdd? 2. Your neighbor has twelve children. One is blue eye color and short. Two are brown eye color and short. Two are blue eye color and tall. Seven look just like the parents; brown eye color with tall. What can you discover about the genetics of eye color and height of the children? a. How many traits are you dealing with? Each trait has phenotypes: Specify the phenotypes. b. What is the probability of the height of the children? What is the probability of the eye color of the children? (Refer to monohybrid punnett square slides 17-19) c. What are recessive traits based on the…

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Short Answer 3. The pedigree shown is of a family with an X-linked recessive disease. The sex chromosomes are indicated. Individual II-2 is the result of a non-disjunction event in one of the parents. I || 1 2 XHXH XhY XhY 12 XhXhY A) If the nondisjunction event that gave rise to Il-2 occurred in the father, in which phase of meiosis did it happen? Explain your reasoning. B) Upon further testing, it is discovered that Individual 1-1 has a mild case of the disease. Please give a short explanation as to how that is possible.

Short Answer 4. You identify two recessive mutations in fruit flies, one that results in curly wings (cc) and one in an ebony body (ee). You cross two flies that are heterozygous for both traits (CcEe), and find 352 flies progeny in the next generation with the following phenotypes: wild type - 193 wild type wings, ebony body - 69 You believe the curly and ebony alleles assort independently and are not linked. Perform a chi square analysis for this cross to test the null hypothesis. A) Show at least the following parts of your work: the expected vs. observed numbers for each phenotype, and the final X² value. Observed Expected (o-e)²/e wild type body, curly wings - 64 curly wings, ebony body - 26 Edit View Insert Format Tools 12pt ✓ Paragraph Table X² U AV T² v BIUA V V QV G✓ ⠀