Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN: 9780134580999
Author: Elaine N. Marieb, Katja N. Hoehn
Publisher: PEARSON
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In Drosophila flies, the allele b gives a black body, and the allele b+ gives brown, the wild-type
Make a linkage map of the three genes. Compute for interference and explain what the derived value means. Show complete solutions to support your answers
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- Miniature wings in Drosophila result from an X-linked allele (w) that is recessive to the allele for long wings (+). In a cross of a long winged male with a long winged female, the following offspring were obtained: 100 long winged males, 106 miniature winged males, and 480 long winged females. Given this result, the female must be a carrier of the miniature wing allele. True Falsearrow_forwardIn D. melanogaster, reduced bristles (rd), cinnabar eyes (cn), and vestigial wings (vg) are recessive traits located on chromosome II in that order. The distance between rd and cn is 7 cM and the distance between cn and vg is 9 cM. The CoC for this chromosome is 0.9. A true-breeding female expressing cinnabar eyes and vestigial wings is crossed to a true-breeding male expressing reduced bristles. The F1 are wild type. An F1 female is then test crossed to a male expressing all three traits. Among the F2 progeny, how often would you expect to observe flies expressing only cinnabar eyes? Using the same information from above, among the F2 progeny, how often would you expect to observe flies expressing only vestigial wings?arrow_forwardIn Drosophila, males from a true-breeding stock with raspberry-colored eyes were mated to females from a true-breeding stock with sable-colored bodies. In the F1 generation, all the females had wild-type eye and body color, while all the males had wild-type eye color but sable-colored bodies. When F1 males and females were mated to each other, the F2 was composed of: 216 females with wild-type eyes and wild-type bodies 223 females with wild-type eyes and sable bodies 191 males with wild-type eyes and sable bodies 188 males with raspberry eyes and wild-type bodies 23 males with wild-type eyes and bodies 27 males with raspberry eyes and sable bodies Which statements are consistent with the above data? (Select all correct answers.) The alleles causing the raspberry-colored eye and sable-colored body phenotypes are dominant to the corresponding wild-type alleles The genes controlling raspberry-colored eyes and sable-colored bodies map…arrow_forward
- In the fruit fly, dumpy wings (d) and purple eyes (p) are encoded by mutant alleles that are recessive to those that produce wild type traits; long wings (d+) and red eyes (p+). These two genes are on the same chromosome. In a particular lab, two researchers Walt and Jesse crossed a fly homozygous for dumpy wings and purple eyes with a fly homozygous for the wild type traits. The F1 progeny, which had long wings and red eyes, was then crossed with flies that had dumpy wings and purple eyes. Unfortunately, the progeny of this cross somehow escaped. To prevent their other projects from contamination, they decided to spend an exceptionally boring hour in the lab catching and counting the progeny and found the following: long wings, red eyes – 482 dumpy wings, purple eyes – 473 long wings, purple eyes – 23 dumpy wings, red eyes - 22 What is the genetic distance between these two loci? a. 4.5 cM b. 55 cM c. 45 cM d. 49.5 cM e. 4.7 cMarrow_forwardConsider the following three autosomal recessive mutations in Drosophila:vestigial wings (v); wild type is long (v+)black body color (b); wildtype is gray (b+)plum eyes (p); wildtype is red (p+)A vestigal, gray, red female (homozygous for all three genes) is crossed with a long wing, black, plum male (homozygous for all three genes). The F1 female progeny are mated with triple homozygous recessive males. Here is the phenotypic data for the F2 progeny:vestigal; gray; red 580long wings; black; plum 592vestigal; black; red 45long; gray; plum 40vestigal; black; plum 89long; gray; red 94vestigal; gray; plum 3long; black; red 5A total of 1448 progeny were counted.Which one of the following values is the approximate distance between the plum eye color and black body color loci?arrow_forwardSET 2: In corn, the following allelic pairs have been identified in chromosome 3: +/b plant color booster vs. non-booster +/lg with ligule vs. without ligule +/v green plant vs. virescent A test cross between triple recessive plants and plants heterozygous for the three pairs gave the following progeny: + v lg 305 b + lg b v lg + + lg b v + 148 58 + + + 62 + y + 152 b + + 275 Total 1000 Calculate the parental and recombinant frequencies, the map distances between genes, and the coefficient of coincidence. Illustrate the gene map or sequence.arrow_forward
- Vermilion eye color in Drosophila is sex-linked and recessive. What would be the phenotypes of maleand female progenies of a cross between a 6 vermilion female and 6 wild-type (red) male. what is the f1 and f2 generation. if a reciprocal cross is done containing 6 WT females with 6 mutant males what is the F1 and F2 generation. Do they contain the single gene or double gene?arrow_forwardIn Drosophila, a heterozygous female for the X-linkedrecessive traits a, b, and c was crossed to a male that phenotypically expressed a, b, and c. The offspring occurred inthe following phenotypic ratios.+ b c 460a + + 450a b c 32+ + + 38a + c 11+ b + 9 No other phenotypes were observed.(a) What is the genotypic arrangement of the alleles ofthese genes on the X chromosome of the female?arrow_forwardYou are doing a cross with Drosophila using the following two traits. Curly wings is dominant over straight wings, and round eyes is dominant over elliptical eyes. You cross a female fly that is known to be heterozygous for both genes with a male that is heterozygous for the wing gene but has elliptical eyes. This cross produces 74 flies with curly wings and round eyes, 61 with curly wings and elliptical eyes, 24 with straight wings and round eyes, and 21 with straight wing and elliptical eyes. Calculate the expected phenotype ratios for this cross, then use the chi-square test to see if the observed data are consistent with the expected numbers.arrow_forward
- In Drosophila, the allele for long legs (sl*) is wild-type and the allele for short legs (sl) is mutant. The allele for gray body color (b*) is wild-type and the allele for black body color (b') is mutant. The loci for leg length and body color are linked. Flies with sl*sl* b*b* genotypes are mated with flies that have sl s bb genotypes. A testcross was then performed in which the F, offspring with sl*sl b*b genotypes were mated with flies with sl sl. b'b genotypes. The phenotypes of 1000 offspring were recorded. There were 470 flies with long legs and grey body, 30 flies with long legs and black body, 30 flies with short legs and grey body, and 470 flies with short legs and black body. Which of these phenotypes are parental phenotypes? VWhich of these phenotypes are recombinant phenotypes? What is the distance between these two gene loci in centiMorgans (map units)?arrow_forwardFemales of wild-type Strain A and males of mutant Strain B, as well as females of mutant Strain B and males of wild-type Strain A, make reciprocal crosses. Explain why reciprocal crosses are needed in genetics experiments involving Drosophila fruit flies.arrow_forwardA D. melanogaster male is homozygous for a translocation between chromosomes 2 and 3. This fly is otherwise wild-type. This male is crossed to a female fly that is homozygous for normal chromosome order and is homozygous for dumpy wings (dy), a recessive on chromosome 2 and sepia eyes (se), a recessive on chromosome 3. A male progeny from the above cross is test-crossed to a female fly that is homozygous for dy and se. What progeny phenotypes and frequencies are expected from this second cross? Answer choices 1/2 wild-type and 1/2 dumpy and sepia 1/4 wild-type, 1/4 dumpy, 1/4 sepia, 1/4 dumpy and sepia All dumpy and sepia 2/3 wild-type, 1/3 dumpy and sepia 9/16 wild-type, 3/16 dumpy, 3/16 sepia, 1/16 dumpy and sepiaarrow_forward
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