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In animals, embryonic lethal mutations can either in zygotic or maternal effect. In zygotic embryo lethal mutations, the genotype of the embryo determines the
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- Below is a pedigree of a family with a history of Best disease (or vitelliform macular dystrophy). All members of this family underwent ASO testing using two different oligonucleotides (ASO 1 and ASO 2): one that hybridizes to the only known mutation that leads to Best disease and one that hybridizes to the wild-type gene sequence in the same region. From the information you have, how is Best disease most likely inherited? 1. II. III. 0 0 0 0 0 1 ? autosomal dominant autosomal recessive x-linked recessive x-linked dominant you cannot determine ASO 1 ASO 2 1-1 1-2 II-1 11-2 11-3arrow_forwardIn c. elegans, genetics model organism, movement problems (unc) and small body size (sma) are encoded by two mutant alleles that are recessive to those that produce wild-type traits (unc+ and sma+). A worm homozygous for movement problems and small body is crossed with a worm homozygous for the wild-type traits. The F1 have normal movement and normal body size. The F1 are then crossed with worms that have movement problems and small body size in a testcross. The progeny of this testcross is: Normal movement, normal body size 210 Movement problems, normal body size 9 Normal movement, small body size 11 Movement problems, small body size 193 a)From the test cross results, can you tell if the two genes are on the same chromosome or not? Explain your reasoning. b)What phenotypic proportions would be expected if the genes for round eyes and white body were located on different chromosomes? (please explain hot to get to these conclusions)arrow_forwardWe will see an MII pattern when: There is no crossover between a gene and its centromere There is crossover between two genes There is crossover between two centromeres There is crossover between a gene and its centromere There is no crossover between two genesarrow_forward
- Predict the probability (using a Punnett square) of producing an offspring affected by a single gene X-linked mutation given the genotype of the parents. Compare these crosses in two cases: where the mutant allele is “A” vs where the mutant allele is “a” (XAXA x XaY) (XAXa x XAY) (XAXa x XaY) (XaXa x XAY) (XaXa x XaY). Include gender in the phenotype.arrow_forwardRetinoblastoma can be seen as a familial cancer, inherited in an autosomal recessive manner (RB-/RB-), individuals heterozygous for the RB+ and RB- alleles can develop tumor as a result of… A mitotic crossover that leads to homozygosity for RB+ in some cells and RB- in other cells A meiotic mutation in the RB+ allele that leads to homozygosity for RB+ A somatic mutation in the RB- allele that leads to homozygosity for RB+ The fact that RB- is dominant to RB+arrow_forwardIn 1952, an article in the British Medical Journalreported interesting differences in the behavior ofblood plasma obtained from several people who suffered from X-linked recessive hemophilia. Whenmixed together, the cell-free blood plasma from certain combinations of individuals could form clots inthe test tube. For example, the following table showswhether clots could form (+) or not (−) in variouscombinations of plasma from four people withhemophilia:1 and 1 − 2 and 3 +1 and 2 − 2 and 4 +1 and 3 + 3 and 3 −1 and 4 + 3 and 4 −2 and 2 − 4 and 4 −What do these data tell you about the inheritance ofhemophilia in these individuals? Do these data allowyou to exclude any models for the biochemical pathway governing blood clotting?arrow_forward
- Males of many diploid species (like us) have X and Y sex chromosomes. They are hemizygous for most X- linked genes. Thus, males express most X-linked alleles, whether they are dominant or recessive in females. In the fruit fly Drosophila, it is common to achieve the equivalent of a test cross of X-linked genes in females by assessing the readily observed phenotypes of their male progeny. Since males do not receive X-linked genes from their father, sires of these crosses can be normal or wild-type flies. In fly genetics, it is conventional to name a gene after the mutant phenotype that enabled its discovery. Your challenge is to establish gene order and map distances between three X-linked genes in Drosophila. Each gene is represented by recessive mutant alleles that express rather distinctive phenotypes relative to their dominant wild-type alternative alleles. Flies expressing fruitless (f) are bisexual, lush (1) have a heightened responses to ethanol, and ken&barbie (kb) lack external…arrow_forwardWhich of the following statements about calico cats is true? Select all that apply.arrow_forwardA blue eyed agouti hair male mouse is mated to a brown eyed yellow haired female mouse, and a test cross is performed with the F1. Both blue eyes and yellow hair are recessive phenotypes. What is the probability of a recovering a phenotypically blue-eyed yellow haired mouse in the F2 if: eye color and hair color genes are 30 map units apart on the same autosomearrow_forward
- In water snakes, there are three different possible skin colors: Brown, Gray & Green. BB=Brown BG=Gray GG=Green What are the possible genotypes & phenotypes from crossing a brown & gray snake? What type of gene action is being expressed in this example?arrow_forwardWhat is the probability of Sister 3 as a carrier of the death gene?arrow_forward
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