In a volumetric analysis experiment, an acidic aqueous solution of methanol (CH3OH) is titrated with a solutloh of po dichromate (K2Cr207)according to the following balanced chemical equation: 2K2Cr207(aq) + 8H2SO4(aq) + 3CH3OH(aq) ------> 2Cr2(SO4)3(aq) + 11H20() + (aq) + 2K2SO4(aq) What volume of 0.00181 M K½Cr2O7 is required to titrate 1.75 g of CH3OH? Hint: Convert 1.75 g CH3OH into its moles , then using the equation convert it to moles of K2Cr207. use the molarity of K2Cr,O7 to convert it into its volume.

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In a volumetric analysis experiment, an acidic aqueous solution of methanol (CH3OH) is titrated with a solutloh of po
dichromate (K2Cr207)according to the following balanced chemical equation:
2K2Cr207(aq) + 8H2SO4(aq) + 3CH3OH(aq) ------> 2Cr2(SO4)3(aq) + 11H20() + (aq) + 2K2SO4(aq)
What volume of 0.00181 M K½Cr2O7 is required to titrate 1.75 g of CH3OH?
Hint: Convert 1.75 g CH3OH into its moles , then using the equation convert it to moles of K2Cr207. use the molarity of K2Cr,O7 to
convert it into its volume.
Transcribed Image Text:In a volumetric analysis experiment, an acidic aqueous solution of methanol (CH3OH) is titrated with a solutloh of po dichromate (K2Cr207)according to the following balanced chemical equation: 2K2Cr207(aq) + 8H2SO4(aq) + 3CH3OH(aq) ------> 2Cr2(SO4)3(aq) + 11H20() + (aq) + 2K2SO4(aq) What volume of 0.00181 M K½Cr2O7 is required to titrate 1.75 g of CH3OH? Hint: Convert 1.75 g CH3OH into its moles , then using the equation convert it to moles of K2Cr207. use the molarity of K2Cr,O7 to convert it into its volume.
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