MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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In a survey of
3213
adults aged 57 through 85 years, it was found that
83.9%
of them used at least one prescription medication. Complete parts (a) through (c) below.
a. how many of the 3213 subjects used at least one prescription medication?
b. construct a 90% confidence
c. what do the results tell us about the proportion of college students who use at least one prescription medication?
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- In a survey of 3116 adults aged 57 through 85 years, it was found that 86.2% of them used at least one prescription medication. Complete parts (a) through (c) below. a. How many of the 3116 subjects used at least one prescription medication? b. Construct a 90% confidence interval estimate of the percentage of adults aged 57 through 85 years who use at least one prescription medication. c. What do the results tell us about the proportion of college students who use at least one prescription medication? A. The results tell us that there is a 90% probability that the true proportion of college students who use at least one prescription medication is in the interval found in part (b). B. The results tell us that, with 90% confidence, the probability that a college student uses at least one prescription medication is in the interval found in part (b). C. The results tell us that, with 90% confidence, the true proportion of college students who use at…arrow_forwardA survey of several 11 to 12 year olds recorded the following amounts spent on a trip to the mall: $19.55,$25.44,$25.80,$14.87,$11.83,$19.89 Construct the 80% confidence interval for the average amount spent by 11 to 12 year olds on a trip to the mall. Assume the population is approximately normal. Step 1 of 4 : Calculate the sample mean for the given sample data. Round your answer to two decimal places.arrow_forwardConstruct a 95% confidence interval for p1 - p2 for a survey that finds 30% of 240 males and 41% of 200 females are opposed to the death penalty. Group of answer choices a.(-0.200, -0.021) b.(-1.532, 1.342) c.(-1.324, 1.512) d.(-0.561, 0.651)arrow_forward
- Given the following: Sample Mean = 84.3 Population Variance = 144 Sample size = 35 a. Calculate a 90% confidence interval for the mean. Interpret this interval. b. Calculate a 99% confidence interval for the mean. c. Explain the relationship between Confidence Levels and the resulting intervals.arrow_forwardAccording to recent data by the American Marketing Association, 76.5%of people in the 18-24 age group used social media in 2017. You want to find out what the social media proportion is among your classmates who are all between 18 and 24 years old. Suppose you obtain a random sample of 229 students and find that 202 students in this sample are active social media users. Complete parts a through c below. a. Construct a 99% confidence interval to estimate the actual proportion of social media users. A 99% confidence interval to estimate the actual proportion has a lower limit of------ and an upper limit of------- (Round to three decimal places as needed.) b. What is the margin of error for this sample? c. Is there evidence that this proportion matches that of the overall population based on the sample?arrow_forwardWhen constructing a 90% confidence interval around a sample mean, how many samples out of 100 would you expect to not include the true population mean within their confidence intervals? a. 5 b. 1 c. 0 d. 10arrow_forward
- University Food service is interested in the percentage of students on campus who would choose a vegan meal if offered (as an addition to a menu that contained a vegetarian and non-vegetarian option). They receive responses from 45 students and find that 13 of them would at least occasionally purchase that choice. A. Construct a 95% confidence interval. B. Briefly interpret this interval in the context of the problem.arrow_forwardSuppose we wish to estimate the average number of hours per week that Americans watch TV. Use the following data from an SRS to find a 90% confidence interval: 30 64 49 40 21 58 9 43 39 43arrow_forwardWe randomly sample 218 individuals and find that 97 have a college degree. a.)Construct a 95% confidence interval. b.) Describe our interpretation of the confidence level.arrow_forward
- 17arrow_forwardTen engineering schools in the US were surveyed. the sample contains 250 electrical engineers, 80 being women; 175 chemical engineers, 40 being women. Compute a 90% confidence interval for the difference between the proportions of women in these two fields of engineering. Select one: O a. (0.02, 0.16) Ob. (0.01, 0.17] O. (0.04, 0.14) O d. [0.03, 0.15]arrow_forward
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