In a survey, 10 people were asked how much they spent on their child's last birthday gift. The results were roughly bell-shaped with a mean of $33 and standard deviation of $13. Construct a confidence interval at a 99% confidence level. Give your answers to one decimal place. __________± ___________

You are interested in finding a 98% confidence interval for the average commute that non-residential students have to their college. The data below show the number of commute miles for 11 randomly selected non-residential college students. Round answers to 3 decimal places where possible.   18 18 27 17 15 7 11 15 9 12 19 a. With 98% confidence the population mean commute for non-residential college students is between _____  and____miles. b. If many groups of 11 randomly selected non-residential college students are surveyed, then a different confidence interval would be produced from each group. About (____)  percent of these confidence intervals will contain the true population mean number of commute miles and about(_____)   percent will not contain the true population mean number of commute miles.

You measure 43 backpacks' weights, and find they have a mean weight of 65 ounces. Assume the population standard deviation is 9.3 ounces. Based on this, construct a 95% confidence interval for the true population mean backpack weight.Give your answers as decimals, to two places______ ± ________ounces

A survey of 50 young professionals found that they spent an average of ​$24.15w hen dining​ out, with a standard deviation of ​$12.06.   Can you conclude statistically that the population mean is greater than ​$27​? Use a​ 95% confidence interval is.   The​ 95% confidence interval is _____ , _______As ​$27 is__________ of the confidence​ interval, we________ , conclude that the population mean is greater than ​$27. ​(Use ascending order. Round to four decimal places as​ needed.)