In a study of the accuracy of fast food drive-through orders, McDonald’s had 33 orders that were not accurate among 362 orders. Burger King had 40 orders that were not accurate among 400 orders. Construct a 95% confidence interval around the difference in the proportions of inaccurate orders for the two restaurants. Recall the formula for margin or error

Q: 2. Suppose that you take a random sample of 360 people who voted in the last election in a heavily…

A:

Q: In a Gallup poll of 804 randomly selected adults living in the 50 U.S. states and the District of…

A: Answer x =466n =804Confidence interval =95%

Q: In your work for a real estate company, you find that in a sample of 1762 home buyers, 722 found…

A: Given Data: x=722 n=1762   p^=7221762=0.4098

Q: CareerBuilder took a random sample of 1,600 workers and found that 592 of them would put in their…

A: given data sample size (n) =1600favorable outcomes (x) = 59290% ci p.

Q: A survey of 700 non-fatal accidents showed that 167 involved uninsured drivers. Construct a 99%…

A: Given data,n=700x=167Point estimate isp=xn=167700=0.2386Construct a 99% confidence interval?

Q: A university dean is interested in determining the proportion of students who receive some sort of…

A: Given data, n=152 x=101 p=x/n =0.664 The 95% CI is Zc=1.96

Q: A university dean is interested in determining the proportion of students who receive some sort of…

A: It is given that Sample size n = 250 Number of students receiving scholarship, X = 70 The critical…

Q: 3. A survey of 2,950 Filipinos showed that 2,655 trust the Supreme Court decisions on legal issues.…

A: Let X be the number of trust the supreme court decision on legal issues  n be the sample size  Given…

Q: We surveyed 53 people in an attempt to determine the proportion of Americans who lease a vehicle. 13…

A: The proportion of sample Americans who lease a vehicle is, Thus, the proportion of sample Americans…

Q: In a recent poll, 410 people were asked if they liked dogs, and 24% said they did. Find the Margin…

A: We have to find margin of error.

Q: A television station surveys 200 customers and finds that 23% of customers watch the evening news.…

A: Given data n=200 p=23% confidence level=99%

Q: In a survey of 2000 adults in a recent​ year, 708 made a New​ Year's resolution to eat healthier.…

A: Confidence interval for population proportion is given by, p^ +- z* √(pq/n) At 90% z = 1.645 At 95%…

Q: In a survey of 2113 adults in a recent​ year, 741 made a New​ Year's resolution to eat healthier.…

A:

Q: An accounting firm has 1200 clients. From a random sample of 120 clients, 110 indicated very high…

A: Given : An accounting firm has 1200 clients So,  Population size (N) = 1200 Sample size (n) = 120…

Q: researcher wishes to estimate the proportion of college students who cheat on exams. A poll of 520…

A:

Q: In a survey of 2002 adults in a recent​ year, 701 made a New​ Year's resolution to eat healthier.…

A: Given:

Q: In a survey of 2004 adults in a recent​ year, 717 made a New​ Year's resolution to eat healthier.…

A:

Q: In a recent poll, 410 people were asked if they liked dogs, and 32% said they did. Find the Margin…

A:

Q: In a sample of 500 Canadians, 275 say they would rather retire in the US than in Canada. Calculate…

A:

Q: In a survey of 50,00 people, 80% indicated that they listened to their favorite radio station…

A: Hern= 5000 P^ = 0.80 We have to construct 95% ci for p

Q: In your work for a real estate company, you find that in a sample of 1762 home buyers, 722 found…

A: Givenx=722n=1762p^=7221762p^=0.4098α=1-0.98=0.02α2=0.01zc=z0.01=2.3263         (from z-table)

Q: What proportion of the sample reported that they had been cyberbullied?

A: Givensample size(n)=14795No.of respondents say yes they had been cyberbullied(x1) = 2219No.of…

Q: A research group asked 4488 Americans how they fall asleep, and 536 of them fall asleep on their…

A: Obtain the 90% confidence interval for the percentage of all Americans who fall asleep on their…

Q: In a random sample of 500 adults, 410 described themselves as vegetarians. Construct a 95%…

A: We have been provided with the following information about the adults who describe themselves as…

Q: 324 out of a simple random sample of 400 students hated their online math course. Find a 99%…

A: Given: Number of students that hated the online math course (y) = 324 Number of students (n) = 400…

Q: business conducts a random sample of 89 of its customers and find that 44 of them think the company…

A:

Q: According to Thomson Financial, through January 25, 2018, the majority of companies reported profits…

A: The sample proportion of companies showed beat estimates is, p^=104162=0.6420 The sample proportion…

Q: A research institute poll asked respondents if they felt vulnerable to identity theft. In the​ poll,…

A: Given , n = 1008 x = 598

Q: in a recent poll, 220 people were asked if they liked dogs, and 36% said they did . find the margin…

A:

Q: 2. Construct a 95% confidence interval to estimate the proportion of Wingate female students that…

A: total number of female students =181 number of students who are left handed=15

Q: In a survey of 1000 people, 850 said they would not to travel to Disney World this summer. Construct…

A: Given: n=1000 and x=850 Then,p^=xn=8501000=0.85

Q: t poll, 240 people were asked if they liked dogs, and 35% said they did. Find the Margin of Error…

A: Given: n = 240 p^=35%=0.35 The value of z at 95% confidence level is 1.96, which can be obtained by…

Q: A survey of 800 women shoppers found that 15% of them shop on impulse.  What is the 95% confidence…

A: n = 800p^ = 0.1595% CI for p = ?

Q: An interactive poll found that 397 of 2,391 adults aged 18 or older have at least one tattoo. A.…

A: Given data: Sample size (n) = 2391 x = 397 adults To construct: 1.95 % confidence interval 2.98%…

Q: In a survey of 3983 ​adults, 747 oppose allowing transgender students to use the bathrooms of the…

A:

Q: In a recent poll, 289 people were asked if they liked dogs, and 17% said they did. Find the margin…

A: Let X be the number of people who liked dogs Given: Number of people or sample size (n) = 289…

Q: A new survey found that out of a random sample of 300 high school students throughout the country…

A: From the provided information, Sample size (n) = 300 83% of them still planned on taking the…

Q: Suppose that insurance companies did a survey. They randomly surveyed 450 drivers and found that 310…

A: Obtain 95% confidence interval for the population proportion that claim to always buckle up. The 95%…

Q: A researcher wanted to compare the percentages of men and women who play the lottery.  They randomly…

A:

Q: An ice cream shop wants to know how many customers enjoy their newest flavor. 200 randomly selected…

A:

Q: A university dean is interested in determining the proportion of students who receive some sort of…

A: Given that, X = 118 N = 200 99% confidence level

Q: In 2009, 33% of Americans felt that one parent should stay home to raise the children instead of…

A: Given,n=1015x=416p^=xnp^=4161015=0.4099α=1-0.99=0.01α=0.01

Q: wenty years ago, a very famous psychologist specializing in marriage counseling authored a book…

A: Solution: Given information n= 275 Sample size of couples who bought book. X= 217  stayed together…

Q: Find 90% confidence interval for the true proportion of all medical students who plan to work in a…

A: Given : Sample Size, n = 300 Number of successes, x = 30

Q: In a recent poll, 430 people were asked if they liked dogs, and 54% said they did. Find the margin…

A: In a recent poll, 430 people were asked if they liked dogs, and 54% said they did. Find the margin…

Q: Find the margin of error for the​ 99% confidence interval used to estimate the population…

A: p^ : Sample Proportion 35% of the patients showed improvement. So, probability that a patient shows…

Q: In a random sample of 250 high school students, it was found that 85.2% (213) of them later…

A:

Q: f 260 employees selected randomly from one company, 18.46% of them commute by carpooling. Construct…

A: Given data, n=260 p=18.46% =0.1846 z-value at 98% confidence is Zc=2.326

2-Proportion Test

In a 2-proportion test, two separate proportions are measured at the same time, and their similarity is evaluated. It is also known as a 2-proportion z-test, and a comparison of two different proportions is done in this method.