In a study of cell phone use and brain hemispheric​ dominance, an Internet survey was​ e-mailed to 2349 subjects randomly selected from an online group involved with ears. 1068 surveys were returned. Construct a 90​% confidence interval for the proportion of returned surveys.   LOADING... Click the icon to view a table of z scores. ​a) Find the best point estimate of the population proportion p.     ​(Round to three decimal places as​ needed.) ​b) Identify the value of the margin of error E.   E=nothing ​(Round to three decimal places as​ needed.) ​c) Construct the confidence interval.   nothing

MATLAB: An Introduction with Applications
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Author:Amos Gilat
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In a study of cell phone use and brain hemispheric​ dominance, an Internet survey was​ e-mailed to
2349
subjects randomly selected from an online group involved with ears.
1068
surveys were returned. Construct a
90​%
confidence interval for the proportion of returned surveys.
 
LOADING...
Click the icon to view a table of z scores.
​a) Find the best point estimate of the population proportion p.
 
 
​(Round to three decimal places as​ needed.)
​b) Identify the value of the margin of error E.
 
E=nothing
​(Round to three decimal places as​ needed.)
​c) Construct the confidence interval.
 
nothing<p<nothing
​(Round to three decimal places as​ needed.)
​d) Write a statement that correctly interprets the confidence interval. Choose the correct answer below.
 
 
A.
One has
90​%
confidence that the sample proportion is equal to the population proportion.
 
B.
One has
90​%
confidence that the interval from the lower bound to the upper bound actually does contain the true value of the population proportion.
 
C.
There is a
90​%
chance that the true value of the population proportion will fall between the lower bound and the upper bound.
 
D.
90​%
of sample proportions will fall between the lower bound and the upper bound.
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