In a study of cell phone use and brain hemispheric dominance, an Internet survey was e-mailed to 2470 subjects randomly selected from an online group involved with ears. 1029 surveys were returned. Construct a 95% confidence interval for the proportion of returned surveys. a) Find the best point estimate of the population proportion p. b)Identify the value of the margin of error E. c)Identify the value of the margin of error E. (Round to three decimal places as needed.) Thank you so much
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Q: Use the sample data and confidence level given below to complete parts (a) through (d). In a study…
A: a) Suppose, p is the true proportion of returned surveys.
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Q: Use the sample data and confidence level given below to complete parts (a) through (d). In a study…
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A: The formula for computing confidence interval is, n is the sample size and P is the proportion.
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A: It is given that Favourable cases, X = 970 Sample size, n = 2577 Confidence level = 90%
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Q: Use the sample data and confidence level given below to complete parts (a) through (d). In a…
A: Solution: Given information: n= 2670 Sample size of subjects x= 1149 subjects were returned…
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Q: Use the sample data and confidence level given below to complete parts (a) through (d). In a study…
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Q: Use the sample data and confidence level given below to complete parts (a) through (d). In a study…
A: Givenx=1036n=2566confidence lnterval = 95%
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A: Step 1:(a) To find the best point estimate of the population proportion ppp, we use the sample…
Q: Use the sample data and confidence level given below to complete parts (a) through (d). A research…
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Q: a) Find the best point estimate of the population proportion p. (Round to three decimal places as…
A: Given that Sample size n =2531 Favorable cases x =1092 NOTE:- According to bartleby guidelines…
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A: Givensample size(n)=23sample mean (x) = 31standard deviation (s) = 8α = 1-0.95=0.05α2=0.025degrees…
Q: Use the sample data and confidence level given below to complete parts (a) through (d). In a study…
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A: Given information X = 598, Sample size (n) = 935
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- In a survey of 3213 adults aged 57 through 85 years, it was found that 83.9% of them used at least one prescription medication. Complete parts (a) through (c) below. a. how many of the 3213 subjects used at least one prescription medication? b. construct a 90% confidence interval estimate of the percentage of adults aged 57 through 85 years who use at least one prescription medication. c. what do the results tell us about the proportion of college students who use at least one prescription medication?Use the sample data and confidence level given below to complete parts (a) through (d). In a study of cell phone use and brain hemispheric dominance, an Internet survey was e-mailed to 2543 subjects randomly selected from an online group involved with ears. 1055 surveys were returned. Construct a 99% confidence interval for the proportion of returned surveys. Click the icon to view a table of z scores. a) Find the best point estimate of the population proportion p. (Round to three decimal places as needed.) b) Identify the value of the margin of error E. E = (Round to three decimal places as needed.) c) Construct the confidence interval. OUse the sample data and confidence level given below to complete parts (a) through (d). In a study of cell phone use and brain hemispheric dominance, an Internet survey was e-mailed to 2610 subjects randomly selected from an online group involved with ears. 1052 surveys were returned. Construct a 95% confidence interval for the proportion of returned surveys. Click the icon to view a table of z scores. a) Find the best point estimate of the population proportion p. (Round to three decimal places as needed.) b) Identify the value of the margin of error E. E = (Round to three decimal places as needed.) c) Construct the confidence interval.In a survey, 19 people were asked how much they spent on their child's last birthday gift. The results were roughly bell-shaped with a mean of $42 and standard deviation of $4. Find the margin of error at a 98% confidence level.In a survey, 26 people were asked how much they spent on their child's last birthday gift. The results were roughly bell-shaped with a mean of $40 and standard deviation of $6. Find the margin of error at a 90% confidence level.A college administrator is interested in determining the proportion of students who receive some sort of financial aid. Instead of examining the records for all students, the administrator randomly draws 120 students and finds that 48 of them are receiving financial aid. Use a 90% confidence interval to estimate the true proportion of students who receive financial aid.In a survey, 41 people were asked how much they spent on their child's last birthday gift. The results were roughly bell-shaped with a mean of $36 and standard deviation of $4. Find the margin of error for a 95% confidence level.Use the sample data and confidence level given below to complete parts (a) through (d). In a study of cell phone use and brain hemispheric dominance, an Internet survey was e-mailed to 2540 subjects randomly selected from an online group involved with ears. 1141 surveys were returned. Construct a 90% confidence interval for the proportion of returned surveys. Click the icon to view a table of z scores. a) Find the best point estimate of the population proportion p. (Round to three decimal places as needed.) b) Identify the value of the margin of error E. E= (Round to three decimal places as needed.) c) Construct the confidence interval.Use the sample data and confidence level given below to complete parts (a) through (d). In a study of cell phone use and brain hemispheric dominance, an Internet survey was e-mailed to 2642 subjects randomly selected from an online group involved with ears. 1128 surveys were returned. Construct a 99% confidence interval for the proportion of returned surveys. Click the icon to view a table of z scores. a) Find the best point estimate of the population proportion p. (Round to three decimal places as needed.) b) Identify the value of the margin of error E. E = (Round to three decimal places as needed.) c) Construct the confidence interval.We randomly sample 218 individuals and find that 97 have a college degree. a.)Construct a 95% confidence interval. b.) Describe our interpretation of the confidence level.17In a study by Sallie Mae and Gallup, 323 of the 569respondents said that they paid for their education by taking out student loans. Find a 95% confidence interval for the proportion of students who paid for their education by taking out student loans.Recommended textbooks for youMATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons IncProbability and Statistics for Engineering and th…StatisticsISBN:9781305251809Author:Jay L. 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