In a study of cell phone usage and brain hemispheric dominance, an Intemet survey was e-mailed to 6992 subjects randomly selected from an online group involved with ears. There were 1294 surveys returned. Use a 0.01 significance level to test the claim that the return rate is less than 20%. Use the P-value method and use the normal distribution as an approximation to the binomial distribution. Identify the null hypothesis and alternative hypothesis. OA Ho p<0.2 Hy:p 0.2 O B. Ho: p>0.2 H1 p 0.2 O c. Ho p# 0.2 D. Ho: p 0.2 H p 0.2 H1 p 0.2 OE. Ho p 0.2 O F. Ho p 0.2 H1 p>0.2 Hy:p<0.2 The test statistic is z (Round to two decimal places as needed.) The P-value is (Round to three decimal places as needed.) the significance level, Because the P-value is the null hypothesis. There is evidence to support the claim that the return rate is less than 20%

The president of a large free-standing laboratory claims that 80 percent of his 5,000 customers are satisfied with the service they receive. To test this claim, a MT research group surveyed 100 customers, using simple random sampling. Among the sampled customers, 73 percent say they are satisfied. Based on these findings, can we reject the president's hypothesis that 80% of the customers are very satisfied? Use a 0.05 level of significance.

Consider a sample of 50 football​ games, where 27 of them were won by the home team. Use a 0.05 significance level to test the claim that the probability that the home team wins is greater than​ one-half. What is the P-Value?

In a study of cell phone usage and brain hemispheric​ dominance, an Internet survey was​ e-mailed to 6956subjects randomly selected from an online group involved with ears. There were 1290 surveys returned. Use a 0.01 significance level to test the claim that the return rate is less than​ 20%. Use the​ P-value method and use the normal distribution as an approximation to the binomial distribution. Identify the null hypothesis and alternative hypothesis.     A. H0​: p=0.2 H1​: p≠0.2   B. H0​: p=0.2 H1​: p<0.2   C. H0​: p>0.2 H1​: p=0.2   D. H0​: p≠0.2 H1​: p=0.2   E. H0​: p=0.2 H1​: p>0.2   F. H0​: p<0.2 H1​: p=0.2 The test statistic is z= ​(Round to two decimal places as​ needed.) The​ P-value is   ​(Round to three decimal places as​ needed.) Because the​ P-value is ▼   greater than less than the significance​ level, ▼   fail to reject reject the null hypothesis. There is ▼   insufficient…

A certain drug is used to treat asthma. In a clinical trial of the drug, 18 of 282 treated subjects experienced headaches (based on data from the manufacturer). The accompanying calculator display shows results from a test of the claim that less than 11​% of treated subjects experienced headaches. Use the normal distribution as an approximation to the binomial distribution and assume a 0.05 significance level.  What is the final conclusion?     A. There is sufficient evidence support the claim that less than 11% of treated subjects experienced headaches.   B. There is not sufficient evidence to warrant rejection of the claim that less than 11% of treated subjects experienced headaches.   C. There is not sufficient evidence support the claim that less than 11% of treated subjects experienced headaches.   D. There is sufficient evidence to warrant rejection of the claim that less than 11% of treated subjects experienced headaches

A machine produces bolts with an average length of 16 inches. A manager selects a sample of 25 bolts. The average length in the sample was 15.95 inches with a variance of 0.4 inches.The acceptable variance for the length is 0.3 inches. (Note that 1 inch is equivalent to 2.54 cm).      a. Construct a 95% confidence interval for the population variance.  b. State the null and alternative hypotheses to test whether or not the population variance equals 0.3 inches.  c. Compute the test statistic.  d. The null hypothesis is to be tested at the 5% level of significance. State the decision rule for the test using the critical value approach.  e. What do you conclude about the population variance?

In a study of 809 randomly selected medical malpractice lawsuits, it was found that 509 of them were dropped or dismissed. Use a 0.01 significance level to test the claim that most medical malpractice lawsuits are dropped or dismissed. Identify the null and alternative hypotheses. The null hypothesis, Ho, is a statement that the value of a population parameter (such as proportion, p, mean, µ, or standard deviation, o) is equal to some claimed value. The alternative hypothesis, H,, is the statement that the parameter has a value that somehow differs from the null hypothesis and uses the inequalities , or #, corresponding to a left, right, or two-tailed test, respectively. 5

Identify the statistic for this hypotheis test.  Identify the p-value for this hypothesis test. Identify the conclusion for this hypothesis test.

In a random sample of​ males, it was found that 25 write with their left hands and 217 do not. In a random sample of​ females, it was found that 58 write with their left hands and 450 do not. Use a .05 significance level to test the claim that the rate of​ left-handedness among males is less than that among females. Identify the test statistic.z=?

In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6990 subjects randomly selected from an online group involved with ears. There were 1347 surveys returned. Use a 0 01 significance level to test the claim that the return rate is less than 20%. Use the P-value method and use the normal diştribution as an approximation to the binomial distribution. Identify the null hypothesis and alternative hypothesis. O A. Ho p>02 H p=02 О В. Но р302 H p0.2 The test statistic is z= (Round to two decimal places as needed.) The P-value is (Round to three decimal places as needed.) the null hypothesis. There is evidence to support the claim that the return rate is less than 20%. Because the P-value is the significance level,