In a program designed to help patients stop smoking, 189 patients were given sustained care, and 83.1% of them were no longer smoking after one month. Use a 0.10 significance level to test the claim that 81% of the patients stopped smoking when giving sustained care. Use the P value method. Use the normal distribution as an approximation to the binomial distribution. Let Pete denote the population proportion of patients who will no longer be smoking after one month when given sustained care period identify the null and alternative hypothesis.

Insurance Company A claims that its customers pay less for car insurance, on average, than customers of its competitor, Company B. You wonder if this is true, so you decide to compare the average monthly costs of similar insurance policies from the two companies. For a random sample of 1313 people who buy insurance from Company A, the mean cost is $151$⁢151 per month with a standard deviation of $16$⁢16. For 99 randomly selected customers of Company B, you find that they pay a mean of $158$⁢158 per month with a standard deviation of $19$⁢19. Assume that both populations are approximately normal and that the population variances are equal to test Company A’s claim at the 0.050.05 level of significance. Let customers of Company A be Population 1 and let customers of Company B be Population 2. Step 2 of 3:  Compute the value of the test statistic. Round your answer to three decimal places.

The average retirement age in America is 64 years old. Do small business owners retire at a younger average age? The data below shows the results of a survey of small business owners who have recently retired. Assume that the distribution of the population is normal. 63, 54, 69, 69, 53, 53, 71, 51, 61, 60, 69, 54 What can be concluded at the the a = 0.01 level of significance level of significance? a. For this study, we should use t-test for a population mean b. The null and alternative hypotheses would be: Но: μν H1: c. The test statistic t (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) II

Do men score lower on average compared to women on their statistics finals? Final exam scores of twelve randomly selected male statistics students and twelve randomly selected female statistics students are shown below. Male: 89 94 88 64 57 58 62 83 82 88 57 78 Female: 81 80 65 66 97 92 70 94 82 90 65 93 Assume both follow a Normal distribution. What can be concluded at the the a = 0.10 level of significance level of significance? For this study, we should use Select an answer a. The null and alternative hypotheses would be: Ho: Select an answer Select an answer Select an answer v (please enter a decimal) H1: Select an answer v Select an answer v Select an answer ♥ (Please enter a decimal) b. The test statistic ? v = (please show your answer to 3 decimal places.) c. The p-value = d. The p-value is ? v a e. Based on this, we should Select an answer v the null hypothesis. f. Thus, the final conclusion is that ... (Please show your answer to 4 decimal places.) O The results are…

A sample of the monthly amounts spent for food by families of four receiving food stamps approximates a symmetrical distribution. The sample mean is $150 and the variance is $400. Using the Empirical Rule, about 95 percent of the monthly food expenditures are between what two amounts? Select one: $85 and $105 Ob. $205 and $220 O $110 and $190 Od. $100 and $200

Periodically, customers of a financial services company are asked to evaluate the company's financial consultants and services. Higher ratings on the client satisfaction survey indicate better service, with 7 the maximum service rating. Independent samples of service ratings for two financial consultants are summarized here. Consultant A has 10 years of experience, whereas consultant B has 1 year of experience. Use a = 0.05 and test to see whether the consultant with more experience has the higher population mean service rating. Assume the population variances are unequal. Consultant A Consultant B n1 = 16 n2 10 X1 = 6,81 X2 = 6.25 %3D S1 = 0.68 S2 = 0.75 (a) State the null and alternative hypotheses. O Hoi H1 - H2 = 0 Hai H1- Hz>0 O Ho: H1 - 42 = 0 Hại H1 - H2# 0 O Ho: H1 - H2 > 0 %3D Ha: H1 - H2 = 0 O Ho: H1 - Hz # 0 Hai Hy - Hz = 0 Hoi H1 - H2 = Hai H1- H2 = 0 (b) Compute the value of the test statistic. (Round your answer to three decimal places.) 19.191 (c) What is the p-value?…

Define what is a factor and a level in an Analysis of Variance (ANOVA). Give me an example of a factor with its levels.