In a sample of 54 men, 35 said that they had less leisure time today than they had 10 years ago. In a sample of 54 women, 43 women said that they had less lelsure time today than they had 10 years ago. At a=0.01, is there a difference in the proportions? Use Pi for the proportion of men with less leisure time.

Pavan

Identify the test statistics, p-value & confidence interval

You want to estimate the mean weight of quarters in circulation. A sample of 60 quarters has a mean weight of 5.682 grams and a standard deviation of 0.061 gram. Use a single value to estimate the mean weight of all quarters. Also, find the 95% confidence interval for the average weight of all quarters. The estimate for the mean weight of all quarters is (Round to three decimal places as needed.) grams. Find the 95% confidence interval for the mean weight of all quarters. grams < p< grams (Round to three decimal places as needed.)

erproduction of uric acid in the body can be an Indication of cell breakdown. This may be an advance indication of illness such as go adult male patlent has taken eleven blood tests for uric acid. The mean concentration was x = 5.30 mg/dl. The distribution of uric rmal, with o = 1.95 mg/dI. a) Find a 95% confidence interval for the population mean concentration of uric acid in this patient's blood. What is the margin of ei lower limit upper limit margin of error (b) What conditions are necessary for your calculations? (Select all that apply.) normal distribution of uric acid uniform distribution of uric acid o is known On is large Oo is unknown (c) Interpret your results in the context of this problem. O The probability that this interval contains the true average uric acid level for this patient is 0.95. O We are 5% confident that the true uric acid level for this patient falls within this interval. O We are 95% confident that the true uric acid level for this patient falls within…

Find the margin of error for a​ 95% confidence interval for estimating the population mean when the sample standard deviation equals 90​, with a sample size of​ (i) 400 and​ (ii) 1521. What is the effect of the sample​ size?       Question content area bottom Part 1 ​(i) Find the margin of error for a​ 95% confidence interval for estimating the population mean when the sample standard deviation equals 90 with a sample size of 400.

Find the value for each ta/2 Prompts Submitted Answers n = 18 for the 99% confidence interval for the Choose a match mean. n = 10 for the 90% confidence interval for the Choose a match mean. n = 15 for the 98% confidence interval for the Choose a match mean.

Please solve for margin of error and sample proportion

Estimate the average weekly TV hours watched by students at this university with 99% confidence. What is the parameter of interest? Single Proportion, Single Mean, Difference in Proportions, Difference in Independent Means, Mean Difference (matched pairs),  What type(s) of variables? One Quantitative One Categorical One Quantitative and One Categorical Two Categorical What conditions need to be checked? what is the formula for the correct Confidence Interval or Test Statistic? Define each variable in the formula and give its value.

State the null and alternative hypotheses for the statistical test described below. Your answer should be an expression composed of symbols: =,≠,<,>,μ,μ1,μ2,p,p1,p2,0.3,ρ,p^,p^1,p^2,r.Testing to see if there is evidence that a proportion is greater than 0.3.   H0:        vs Ha: