In a random sample of 60 professional actors, it was found that 37 were extroverts.  a) let P represent the proportion of all actors who are extroverts. Find a point estimate for P.(Round your answer to four decimal places)  b) Find a 95% confidence interval for p. (Round your answers to two decimal places)  lower limit= upper limit=

Q: A random sample of 300 college freshmen found that 112 of them own an iPhone.  Find a 95% confidence…

A: Given, Favorable Cases XX = 112112 Sample Size NN = 300300

Q: Out of 300 people sampled, 156 had kids. Based on this construct a 90% confidence interval for the…

A: X = 156 N = 300

Q: You are interested in finding a 95% confidence interval for the mean number of visits for physical…

A: Given,mean(x¯)=13.6standard deviation (s)=9.1918sample size(n)=10degrees of…

Q: f n=450 and X = 360, construct a 99% confidence interval.

A:

Q: In a sample of 460 adults, 262 had children. Construct a 95% confidence interval for the true…

A: Provided information: Total number of adults = 460 and 262 had children 95% confidence level

Q: Listed below are the blood pressure measurements taken from the right and left arm of 5 patients.…

A: From the provided information, The mean and standard deviation of the right arm data can be obtained…

Q: A poll of n = 500 randomly selected elementary school students resulted in 110 of them stating…

A:

Q: Suppose we wanted to estimate the average amount of sleep (in hours) a college student gets a night.…

A: Confidence interval : Confidence interval is a range of values it contains the true population…

Q: Out of 100 people sampled, 77 had kids. Based on this, construct a 95% confidence interval for the…

A: We have to find 95% confidence interval for the true population proportion of people with kids.

Q: Lindsey selected a random sample of 25 tomatoes at the farmer's market. The 95% confidence interval…

A: When Lindsey selected a random sample of 25 tomatoes at the farmer's market, she was aiming to…

Q: A sample of 100 homes in city A and 100 homes in City B was taken to estimate the proportion of the…

A: Given that, A sample of 100 homes in city A and 100 homes in city B were taken to estimate the…

Q: A sample of 200 found that 43.2% of those sampled consumed more than 2 alcoholic  beverages  a week.…

A: Given:

Q: Out of 400 people sampled, 232 had kids. Based on this, construct a 95% confidence interval for the…

A:

Q: Out of 400 people sampled, 240 had kids. Based on this, construct a 95% confidence interval for the…

A:

Q: Out of 300 people sampled, 138 had kids. Based on this, construct a 90% confidence interval for the…

A: Given data, n=300 x=138 p=x/n=138/300 =0.46 z-value at 90% confidence is Zc=1.645

Q: A recent survey showed that among 850 randomly selected subjects who completed 4 years of college,…

A: I'm providing the solution below please do refer it and let me know if you have any queries…

Q: sample of 97 psychology graduates found an average salary of $71 K/year. Assume ?=$14 K/year. Find…

A: Given Z score 90% confidence interval=1.645 Sigma=14 n=97

Q: Out of 200 people sampled, 72 had kids. Based on this, construct a 90% confidence interval for the…

A: Givensample size(n)=200x=72sample proportion(p^)=xn=72200=0.36Confidence level=90%

Q: leave all answers to 3 decimals A large public opinion polling agency plans to conduct a national…

A: It is given that  Favourable cases, X = 35 Sample size, n = 100

Q: m what their favorite color was. 23 people said their favorite color is blue. Using this sample,…

A: Sample proportion is the fraction of successful samples and total number of samples. Here,  Total…

Q: Increasing the sample mean would cause a confidence interval to (a) shift left (b) shift right (c)…

A:

Q: A local health centre noted that in a sample of 400 patients, 80 were referred ta hospital. a.…

A: Given, n = 400            x = 80 Therefore, population proportion p^ = 80400 = 0.2 The critical…

Q: According to a report on consumer fraud and identity theft, Indiana had 1671 complaints of identity…

A:

Q: Out of 100 people sampled, 35 had kids. Based on this, construct a 95% confidence interval for the…

A:

Q: Out of 300 people sampled, 228 had kids. Based on this, construct a 90% confidence interval for the…

A: Introduction Sample size, n=300 No. of people who had kids, x=228 CL=0.90

Q: In a random sample of 500 Americans, 25% indicated that they have a cat for a pet. Estimate with 97%…

A:

Q: When 290 college students are randomly surveyed, it is found that 120 own a car. Find a 99%…

A: Given that, x=120,n=290 The sample proportion is, Critical values: By using the standard normal…

Q: In a random sample of 500 Americans, 50% indicated that they have a cat for a pet. Estimate with 95%…

A: Given information

Q: We wish to estimate what percent of adult residents in a certain county are parents. Out of 100…

A: According to the given information, we have Out of 100 adult residents sampled, 88 had kids. 99%…

Q: Out of 300 people sampled, 24 had kids. Based on this, construct a 95% confidence interval for the…

A:

Q: of 100 people sampled, 50 had kids. The best point estimate for p is. The margin of error for a 90%…

A:

Q: Of the 1,000 people, 550 people used company s's smartphone and 460 people used company a's…

A: Given: n= 1000 ,x= 550.0 At 95.0 % confidence level , z score= 1.96 Need to find confidence…

Q: Construct the 99.8% confidence interval for the difference P1 - P2 when x, = 23, n, = 53, x2 = 15,…

A:

Q: Assume that a sample is used to estimate a population proportion p. To find the 95% confidence…

A:

Q: Out of 600 people sampled, 240 have shopped online. Based on this, construct a 90% confidence…

A: Find z-critical value:…

Q: Assume that the following samples are independent. In a random sample of 400 women, 47% favored…

A: Obtain the 98% confidence interval for the difference between the population proportions.   The 98%…

Q: Out of 500 people sampled, 95 had kids. Based on this, construct a 90% confidence interval for the…

A:

Q: Construct a 90​% confidence interval of the population proportion using the given information.…

A: x=240  n=300  p= 240/300 = 0.8 q = 1-p = 1-0.8 = 0.2

Q: Of 102 randomly selected adults, 42 were found to have high blood pressure. A 90% confidence…

A:

Q: Suppose we wish to construct a 95% confidence interval for the population proportion of fans in…

A: Given that, Total fans = 200 130 answered yes 95% confidence level

Q: 2.) A survey of 200 college students revealed that 160 of them eat dessert daily. Construct a 95%…

A:

Q: and X = 96, construct a 90% confidence interval for the population proportion, p. Give your answers…

A: Given X=96 N=120

Q: Out of 400 people sampled, 76 had kids. Based on this, construct a 90% confidence interval for the…

A: Find z-critical value:…

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.