A laboratory electromagnet produces a magnetic field of magnitude 1.51 T. A proton moves through this field with a speed of 5.72 x 106 m/s. (a) Find the magnitude of the maximum magnetic force that could be exerted on the proton. N (b) What is the magnitude of the maximum acceleration of the proton? m/s² (c) Would the field exert the same magnetic force on an electron moving through the field with the same speed? Yes No Explain. (d) Would the electron experience the same acceleration? Yes No Explain.

A 20.0 m long string of Christmas lights has two wires twisted around each other 0.00234 m apart. One carries 3.47 A of current toward the tree and the other carries the same current away from the tree. What is the (+) magnitude of the magnetic force between the wires? [?]N Force (N)

A current-carrying wire is in a B-field and experiences a magnetic force (FB>0). The magnetic force vector is shown below. Choose all the arrows that could represent the current direction. Magnetic force Current direction 45° 45° 45* 45° 45° 40 45° 45°

A charged particle moving through a magnetic field at right angles to the field with a speed of 30.7 m/s experiences a magnetic force of 2.98 x 10-4 N. Determine the magnetic force on an identical particle when it travels through the same magnetic field with a speed of 4.84 m/s at an angle of 32.2° relative to the magnetic field.

Figure 22.57 56. Find the direction and magnitude of the force that each wire experiences in Figure 22.58(a) by, using vector addition.

QUESTION 6 Two long current carrying wires, I and I2, are separated by 2 mm and both carry a current of 8 A. What is the x-component of the magnetic force in newtons on a one meter length of one of the top wire?

When a charged particle moves perpendicularly to the direction of a uniform magnetic field, the direction of the magnetic force is perpendicular to both the direction of the magnetic field and the direction of the velocity of the charged particle.  Accordingly, the charge begins to move in a circular path.  Since the direction of the magnetic force is toward the center of the circular path the charged particle moves along, the magnetic force is a centripetal force (recall centripetal forces from chapter 5 of the text, covered in PHY 2010).  A schematic of such motion is shown below.  The "X"s represent the magnetic field that is directed into the plane of this screen.  The direction of velocity and magnetic force lie within the plane of this screen and are at right angles to one another, as shown below.   If a charge of magnitude 7.45x10-17C, with speed 4.66x106 m/s, and mass 7.12x10-25kg moves within the magnetic field of magnitude 3.96x10-2T, what is the resulting radius of the path…

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