In a live fire exercise, an Army artillery team fires an artillery shell from a howitzer (a relatively small cannon). The barrel makes an angle of 54.0 ° above the horizontal, and the velocity of the projectile as it exits the barrel is 370 m / s. The projectile hits a target on a mountainside 39.0 s after being fired. Assuming that the point where the projectile exits the barrel is the origin, and assuming as usual that the x-axis is horizontal and the y-axis is vertical, find the x and y coordinates, in meters, of the target.

A projectile is launched with an initial velocity 38 m/s and an angle from the horizontal of 45°. The acceleration due to gravity is 9.81 m/s². Assume the projectile is launched from the surface of the Earth. i.e., at y (0) = 0. then the altitude of the projectile as a function of time is: y(t) = gt² + vo sin(0)t Where vo is the initial velocity. What is the maximum altitude achieved by the projectile?

A space vehicle is coasting at a constant velocity of 19.3 m/s in the +y direction relative to a space station. The pilot of the vehicle fires aRCS (reaction control system) thruster, which causes it to accelerate at 0.337 m/2 in the + direction. After 59.8 s, the pilot shuts off the RCS thruster. After the RCS thruster is turned off, find (a) the magnitude and (b) the direction of the vehicle's velocity relative to the space station. Express the direction as an angle (in degrees) measured from the +y direction.

The drawing shows an exaggerated view of a rifle that has been 'sighted in' for a 91.4-meter target. If the muzzle speed of the bullet is Vo = 309 m/s, there are the two possible angles 0₁ and 02 between the rifle barrel and the horizontal such that the bullet will hit the target. One of these angles is so large that it is never used in target shooting. Give your answers as (a) the smaller angle and (b) the larger angle. (Hint: The following trigonometric identity may be useful: 2 sine cose = sin 20.) (a) Number (b) Number Units Units 91.4 m O

A skateboarder shoots off a ramp with a velocity of 7.9 m/s, directed at an angle of 51° above the horizontal. The end of the ramp is 1.4 m above the ground. Let the x axis be parallel to the ground, the +y direction be vertically upward, and take as the origin the point on the ground directly below the top of the ramp. (a) How high above the ground is the highest point that the skateboarder reaches? (b) When the skateboarder reaches the highest point, how far is this point horizontally from the end of the ramp? (a) Number_____  Units_____                                                            (b) Number ____  Units ____

For safety reasons, park rangers decide to start an avalanche on a mountain slope.  They fire an artillery shell at an angle of 520 above the horizontal with an initial speed of 295 m/s.  Thirty seconds later they see the explosion.  What is the x coordinates of the shell where it explodes, relative to the firing point?

A baseball is thrown at an angle θ = 22° above the horizontal with an initial vertical velocity v0y = 13.5 m/s. Use a Cartesian coordinate system with the origin at the baseball's initial position. Calculate the initial horizontal velocity component, v0x in m/s.

An object is launched with an initial velocity of 24.5 m/s at an angle of 37.2 degrees relative to the +x direction. If it is initially at ground level, at what distance away does it return to the ground?

You can use any coordinate system you like in order to solve a projectile motion problem. To demonstrate the truth of this statement, consider a ball thrown off the top of a building with a velocity v at an angle 0 with respect to the horizontal. Let the building be 54.0 m tall, the initial horizontal velocity be 9.10 m/s, and the initial vertical velocity be 10.5 m/s. Choose your coordinates such that the positive y-axis is upward, and the x-axis is to the right, and the origin is at the point where the ball is released. (a) With these choices, find the ball's maximum height above the ground and the time it takes to reach the maximum height. maximum height above ground time to reach maximum height (b) Repeat your calculations choosing the origin at the base of the building. maximum height above ground time to reach maximum height

Mark Watney (played by Matt Damon in the Martian movie) and Marvin the Martian (Looney Tunes cartoon character) are having an argument on the surface of Mars (negligible air resistance). They are testing out their new potato launcher that fires projectiles at a consistent speed. Mark first uses the launcher to launch his potato at an angle of θM = 60◦and then Marvin uses it to launch his identical potato at an angle of θm = 30degrees . The launch speed of the potatoes is v0 = 30 m/s. On mars the acceleration due to gravity is about gm = 3.7 m/s2. (A) Calculate the maximum height each potato achieved. (B) Calculate how far away from the launch each potato landed, assuming they land at the same elevation as from which they were launched.