A skateboarder shoots off a ramp with a velocity of 7.9 m/s, directed at an angle of 51° above the horizontal. The end of the ramp is 1.4 m above the ground. Let the x axis be parallel to the ground, the +y direction be vertically upward, and take as the origin the point on the ground directly below the top of the ramp. (a) How high above the ground is the highest point that the skateboarder reaches? (b) When the skateboarder reaches the highest point, how far is this point horizontally from the end of the ramp? (a) Number_____  Units_____                                                             (b) Number ____  Units ____

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter3: Motion In Two Dimensions
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A skateboarder shoots off a ramp with a velocity of 7.9 m/s, directed at an angle of 51° above the horizontal. The end of the ramp is 1.4 m above the ground. Let the x axis be parallel to the ground, the +y direction be vertically upward, and take as the origin the point on the ground directly below the top of the ramp. (a) How high above the ground is the highest point that the skateboarder reaches? (b) When the skateboarder reaches the highest point, how far is this point horizontally from the end of the ramp?

(a) Number_____  Units_____                                                            

(b) Number ____  Units ____

Expert Solution
Step 1

Given Information:-

Initial speed of the skateboarder is v0=7.9 m/s

Angle θ=51°

Height of the highest point of the ramp from the ground is h0=1.4 m

 

Required:-

We have to calculate height of the highest point reached by the skateboarder and horizontal distance of the highest point from the end of the ramp.

 

Formula:-

We will use the following kinematic equations

vf=vi+at

d=vit+12at2

  vi, vf are initial and final speeds respectively,  a is the acceleration , d is the distance and t is the time.

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