Implement integer division with rounding (not truncation) in MIPS assembly. This can be done by taking the remainder from the division, and dividing the original divisor by this number. If the new quotient is greater than or equal to 1, add 1 to the original quotient. Otherwise do not change the original quotient.

In Java This assignment introduces bitwise-manipulation operators (&, |, <<, >>, >>>, ^, and ~),which are not discussed elsewhere in the book. The bitwise-manipulation operators performsimultaneous bit manipulations and enable programs to process large quantities of binaryinformation efficiently. This project is here because the solution uses a conditional operator.The binary & and | operators can implement bitwise “and” and “or” operations oncorresponding bits in a pair of 32-bit int operands. This bit-manipulation capability enablesJava to efficiently process large quantities of raw binary information. We use this capability toencrypt information sent over the Internet and to process graphical images. Suppose you havea 32-bit pattern of 1’s and 0’s in an integer called mask. You can use mask to either set to 1or reset to 0 any subset of the bits in another integer called data:• data |= mask;1 drives to 1 all bits in data that correspond to 1 bits in…

Prob 7. We have learned in the class that using the barrel shifter, we can implement multiplication/division of a number for some special cases with addition, subtraction, and reversed subtraction instructions as well as shift instructions. For each of the following calculations, write a single-line assembly code to perform it using this approach assuming signed integers A and B are saved in r0 and ri respectively: (a) A = 7 * B / 8 (b) A 7 B/8 5

Implement the modular exponentiation (a.k.a. fast exponentiation)function mod_exp (b, n, m) to compute bn (mod m) more efficiently. (Hint: toread n bit-by-bit, use / and % operations repeatedly)a) Test your function for b = 3, n = 231 – 2, m = 231 – 1.b) Report the result and the time (in seconds) it takes to find the result.   in pahton

By choosing an acceptable pivot and an appropriate cut-off value for the sort, a quicksort's performance may be enhanced.

Write a loop in assembly that increments each element of array x as defined in the previous problem. The size of the array (6) may be hard-coded. Previous Problem array: x dq 43,12,13,53,-1,21

in Java This assignment introduces bitwise-manipulation operators (&, |, <<, >>, >>>, ^, and ~),which are not discussed elsewhere in the book. The bitwise-manipulation operators performsimultaneous bit manipulations and enable programs to process large quantities of binaryinformation efficiently. This project is here because the solution uses a conditional operator.The binary & and | operators can implement bitwise “and” and “or” operations oncorresponding bits in a pair of 32-bit int operands. This bit-manipulation capability enablesJava to efficiently process large quantities of raw binary information. We use this capability toencrypt information sent over the Internet and to process graphical images. Suppose you havea 32-bit pattern of 1’s and 0’s in an integer called mask. You can use mask to either set to 1or reset to 0 any subset of the bits in another integer called data:• data |= mask;1 drives to 1 all bits in data that correspond to 1 bits in…

Bottom: Given b, set the low-order b bits of x to 1; the others to 0. For example, if b is 3, x should be 7. Pay special attention to the edge cases: if b is 32 x should be −1; if b is 0 x should be 0. Do not use - in your solution. Write code in Java. Provided input(s): b Permitted: 40 operations (may use !, ~, +, <<, >>, &, ^, |) Hint: The obvious solution ~(0xFFFFFFFF << b) won’t work. Bit shifts always do a modulo on their right-hand operand, so a << b does the same thing as a << (b % (8*sizeof(a)). Thus, << 32 and << 0 do the same thing.

By choosing an acceptable pivot and a reasonable cut-off value for the sort, one may enhance the performance of a quicksort.