Imagine that you’ve been invited to try out a new hoversuit , and here's how it works: Someone has set up a large flat sheet, many kilometers across, somewhere on the Earth, and they’ve charged the sheet up to a uniform charge density of 3.92 x 10^-6 C. You are issued a special suit that you wear, and it has controls on it which allow you to charge the suit up to any number of Coulombs (C), positive or negative, that you might want. The idea is that you can control the amount of electrical repulsion (or attraction) between the suit and the charged sheet below you. Suppose your mass (including the suit) is 81.2 kg. How much charge must you give the suit if you want to fall up , that is, accelerate upward at the same rate that objects normally accelerate downward due to Earth s gravity? 7.19E-03 C 2.16E-03 C 1.01E-02 C 1.15E-02C

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9. Imagine that you ve been invited to try out a new hoversuit , and here s how it works: Someone has set up a large flat sheet, many kilometers across, somewhere on the Earth, and they ve charged the sheet up to a uniform charge density of 8.52 x 10^-6 C, and your mass including the suit is 87.0 kg. You are issued a special suit that you wear, and it has controls on it which allow you to charge the suit up to any number of Coulombs (C), positive or negative, that you might want. The idea is that you can control the amount of electrical repulsion (or attraction) between the suit and the charged sheet below you. How much charge must you give the suit if you want to fall down toward the sheet, but at the same rate as if you were on the Moon (remembering that the gravitational acceleration on the Moon is 1/6 what it is on Earth)? 2.07E-03 C 2.37E-03 C 2.66E-03 C 1.48E-03 C

Calculate the work required to bring a charge of 5.9×10−95.9×10−9 C from infinity to a point 28.7 cm from a charge of 0.0390.039 μμC in vacuum. Use the value of Coulomb's constant ke=14πε0=9×109ke=14πε0=9×109 m/F. Provide your answer in units of 10−610−6 J: for example, if your answer is 3.6×10−63.6×10−6, then enter 3.6 as your answer.

You've been invited to try out a new hoversuit, and here's how it works: Someone has set up a large flat sheet, many kilometers across, somewhere on the Earth, and they've charged the sheet up to a uniform charge density of  4.11 x 10^-6 C. You are issued a special suit that you wear, and it has controls on it which allow you to charge the suit up to any number of Coulombs (C), positive or negative, that you might want. The idea is that you can control the amount of electrical repulsion (or attraction) between the suit and the charged sheet below you. Suppose your mass (including the suit) is 60.3 kg. How much charge must you give the suit if you want to fall up , that is, accelerate upward at the same rate that objects normally accelerate downward due to Earth s gravity?     4.08E-03 C     6.12E-03 C     9.18E-03 C     5.10E-03C

A particle 1 has a mass of 9.11 x 10^-31 kg and a charge of +1.60 x 10^-19 C. Suppose this particle 1 moves near a particle 2 that has a charge of +3.20 x 10^- 19 C and at all times remains at rest. When particle 1 is 1.4 x 10^-10 m away from particle 2, it is moving away with a speed of 3 x 10^6 m/s. What is the speed of particle 1 when it is a distance of 3.6 x 10^-10 m from particle 2? Answer in mm/s and with two decimal places.

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Two charges, -11.28 nC at PA(12.996, 15.67, 13.59) and 9.62 nC at PB(12.52, 17.87, 15.69), contribute to the electric field at the point P(-17.97, -13.31, -18.88). Find the scalar x-component of the electric field in millivolts per meter at P. Measurements are in meters. Answer in 30 mins pls. Thank you.

THIS IS THE QUESTION THEY ARE REFERRING TOO!!! I ONLY NEED THE SECOND QUESTION ANSWERED!! THANK YOU  Imagine that you ve been invited to try out a new hoversuit , and here s how it works: Someone has set up a large flat sheet, many kilometers across, somewhere on the Earth, and they ve charged the sheet up to a uniform charge density of 1.42 x 10^-6 C/m2. You are issued a special suit that you wear, and it has controls on it which allow you to charge the suit up to any number of Coulombs (C), positive or negative, that you might want. The idea is that you can control the amount of electrical repulsion (or attraction) between the suit and the charged sheet below you. What is the strength of the electric field in the region above the charged sheet? (This is easy, since I m going to give you the formula, which is E = 2 pi k Q/A, where k is the electrical constant and Q/A is the charge density.)   This time the sheet has charge density 2.68 x 10^-6 C, and your mass including the suit is…

During a thunderstorm the electric field at a certain point in the earth's atmosphere is 1.08  105 N/C, directed upward. Find the acceleration of a small piece of ice of mass 1.11  10-4 g, carrying a charge of 1.08  10-11 C.