I'm making an app that reads through an input text file and shows the number of alphanumerical characters, punctuation marks, spaces, etc in the text. The problem is I can't figure out how to make it print out the contents of the file. It is only printing the amount of characters in the title of the text. ```cpp// Close input fileinFile.close();cout << endl << lineCount << " line(s) read from file '" << INPUT_FILE_NAME << "'" << endl << endl;// Count number of alphanumeric charalnum = 0;while (isalnum(INPUT_FILE_NAME[alnum])) alnum++;printf("Alphanumeric chars: %d \n", alnum);// Show application closecout << "End of Text Turtles" << endl;```### Explanation- **Close Input File:** This section of the code is responsible for closing the file that was opened for reading. It outputs to the console how many lines were read from the file specified by `INPUT_FILE_NAME`.- **Count Alphanumeric Characters:** This part initializes a counter `alnum` to zero. It uses a `while` loop to iterate over the string `INPUT_FILE_NAME` to count the number of alphanumeric characters (letters and numbers) present. The count is displayed using `printf`.- **Show Application Close:** At the end of the program, there’s a message printed to indicate the end of the operation, displaying "End of Text Turtles". ## C++ Program to Read from a Text FileThis C++ code demonstrates how to read lines from a text file and display a message in the console. Below is a detailed breakdown of the code:### Code```cppusing namespace std; // So "std::cout" may be abbreviated to "cout"int main(){ // Declare constants const string INPUT_FILE_NAME = ("SampleText1.txt"); // Declare variables ifstream inFile; int lineCount; string line; int anum; // Show application header cout << "Welcome to Text Turtles" << endl; cout << "-----------------------" << endl << endl; // Attempt to open input file inFile.open(INPUT_FILE_NAME); if (!inFile.is_open()) cout << "Error: unable to open file '" << INPUT_FILE_NAME << "'." << endl << endl; else { // Loop to read from input file cout << "Reading lines from file '" << INPUT_FILE_NAME << "' ..." << endl << endl; lineCount = 0; while (inFile.good()) { getline(inFile, line); lineCount = lineCount + 1; } // Close input file inFile.close(); cout << endl << lineCount << " line(s) read from file '" << INPUT_FILE_NAME << "'." << endl << endl; }}```### Explanation- **Include Directive**: The `using namespace std;` directive allows you to use standard library objects like `cout` without prefixing them with `std::`.- **Main Function**: The `main()` function is the starting point of the program, where execution begins.- **Constants and Variables**: Inside the main function, the `INPUT_FILE_NAME` constant is declared, which stores the name of the text file to read. Other variables include `inFile` for file input, `lineCount` to count the lines, `line` for the current line read, and `anum` (though `anum` seems unused in the snippet).- **Output Header**: The program outputs a welcome message, "Welcome to Text Turtles", and a separator line for clarity.- **File Operations**: - Attempts to open the file specified by `INPUT_FILE_NAME`. - If the file cannot

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Computer Networking: A Top-Down Approach (7th Edition)

7th Edition

ISBN:9780133594140

Author:James Kurose, Keith Ross

Publisher:James Kurose, Keith Ross

Chapter1: Computer Networks And The Internet

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I'm making an app that reads through an input text file and shows the number of alphanumerical characters, punctuation marks, spaces, etc in the text. The problem is I can't figure out how to make it print out the contents of the file. It is only printing the amount of characters in the title of the text.