Illustrated below are two identical balls in vacuum, each of mass 0.10 g. They carry identical charges and are suspended by two threads of equal length. At equilibrium they position themselves as shown, separated by a horizontal distance of 40 cm. Your job is to find the charge on each ball and all the forces acting on each ball. 40 L Consider the ball on the left. It is in equilibrium under three forces: (1) the tension FT in the thread, (2) the force of gravity, and the repulsive force Fe. The magnitude of the gravitational force acting on the left ball is The magnitude of the repulsive force acting on the same ball is N. N. Since the left ball is in equilibrium the magnitude of the net force acting on it is 0 N. Fill up the table below for forces acting on the left ball: (include negative signs as needed to do the math correctly) Force x-component Weight 0 y-component -9.8E-4 N FT Fe N 0.001 N N 0 0 N Fnet 0 N

Illustrated below are two identical balls in vacuum, each of mass 0.10 g. They carry identical charges and are suspended by two threads of equal length. At equilibrium they position themselves as shown, separated by a horizontal distance of 40 cm. Your job is to find the charge on each ball and all the forces acting on each ball. 40 L Consider the ball on the left. It is in equilibrium under three forces: (1) the tension FT in the thread, (2) the force of gravity, and the repulsive force Fe. The magnitude of the gravitational force acting on the left ball is The magnitude of the repulsive force acting on the same ball is N. N. Since the left ball is in equilibrium the magnitude of the net force acting on it is 0 N. Fill up the table below for forces acting on the left ball: (include negative signs as needed to do the math correctly) Force x-component Weight 0 y-component -9.8E-4 N FT Fe N 0.001 N N 0 0 N Fnet 0 N

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter19: Electric Forces And Electric Fields

Section: Chapter Questions

Problem 6P

See similar textbooks

Similar questions

Panicle A of charge 3.00 104 C is at the origin, particle B of charge 6.00 104 C is at (4.00 m, 0), and panicle C of charge 1.00 104 C is at (0, 3.00 m). (a) What is the x-component of the electric force exerted by A on C? (b) What is the y-component of the force exerted by A on C? (c) Find the magnitude of the force exerted by B on C. (d) Calculate the x-component of the force exerted by B on C. (e) Calculate the y-component of the force exerted by B on C. (f) Sum the two x-components to obtain the resultant x-component of the electric force acting on C. (g) Repeat part (f) for the y-component. (h) Find the magnitude and direction of the resultant electric force acting on C.
Particle A of charge 3.00 104 C is at the origin, particle B of charge 6.00 101 C is at (4.00 m, 0), and particle C of charge 1.00 104 C is at (0, 3.00 in). We wish to find the net electric force on C. (a) What is the x component of the electric force exerted by A on C? (b) What is the y component of the force exerted by A on C? (c) Kind the magnitude of the force exerted by B on C. (d) Calculate the x component of the force exerted by B on C. (e) Calculate the y component of the force exerted by B on C. (f) Sum the two x components from parts (a) and (d) to obtain the resultant x component of the electric force acting on C. (g) Similarly, find the y component of the resultant force vector acting on C. (h) Kind the magnitude and direction of the resultant electric force acting on C.
Two point charges attract each other with an electric force of magnitude F. If the charge on one of the particles is reduced to one-third its original value and the distance between the particles is doubled, what is the resulting magnitude of the electric force between them? (a) 112F (b) 13F (c) 16F (d) 34F (e) 32F
Panicle A of charge 3.00 104 C is at the origin, particle B of charge 6.00 104 C is at (4.00 m, 0), and panicle C of charge 1.00 104 C is at (0, 3.00 m). (a) What is the x-component of the electric force exerted by A on C? (b) What is the y-component of the force exerted by A on C? (c) Find the magnitude of the force exerted by B on C. (d) Calculate the x-component of the force exerted by B on C. (e) Calculate the y-component of the force exerted by B on C. (f) Sum the two x-components to obtain the resultant x-component of the electric force acting on C. (g) Repeat part (f) for the y-component. (h) Find the magnitude and direction of the resultant electric force acting on C.
Three charged particles are located at the corners of an equilateral triangle as shown in Figure P19.9. Calculate the total electric force on the 7.00-C charge.
An electron and a proton, each starting from rest, are accelerated by the same uniform electric field of 200 N/C. Determine the distance and time for each particle to acquire a kinetic energy of 3.21016 J.
How would you determine whether the charge on a particular rod is positive or negative?
Calculate the angular velocity of an electron orbiting a proton in the hydrogen atom, given the radius of the orbit is 0.5301010 m. You may assume that the proton is stationary and the centripetal force is supplied by Coulomb attraction.
A rod 14.0 cm long is uniformly charged and has a total charge of 22.0 C. Determine (a) the magnitude and (b) the direction of the electric field along the axis of the rod at a point 36.0 cm from its center.
A 1.75-nC charged particle located at the origin is separated by a distance of 0.0825 m from a 2.88-nC charged particle located farther along the positive x axis. If the 1.75-nC particle is kept fixed at the origin, where along the positive x axis should the 2.88-nC particle be located so that the magnitude of the electrostatic force it experiences is twice as great as it was in Problem 27?
Particle A of charge 3.00 104 C is at the origin, particle B of charge 6.00 104 C is at (4.00 m, 0), and particle C of charge 1.00 104 C is at (0, 3.00 m). We wish to find the net electric force on C. (a) What is the x component of the electric force exerted by A on C? (b) What is the y component of the force exerted by A on C? (c) Find the magnitude of the force exerted by B on C. (d) Calculate the x component of the force exerted by B on C. (e) Calculate the y component of the force exerted by B on C. (f) Sum the two x components from parts (a) and (d) to obtain the resultant x component of the electric force acting on C. (g) Similarly, find the y component of the resultant force vector acting on C. (h) Find the magnitude and direction of the resultant electric force acting on C.
A water molecule is made up of two hydrogen atoms and one oxygen atom, with a total of 10 electrons and 10 protons. The molecule is modeled as a dipole with an effective separation d = 3.9 1012 m between its positive and negative charges. What is the magnitude of the water molecules dipole moment?