Chapter6: Gauss's Law
Section: Chapter Questions
Problem 80AP: A 10cm10cm piece of aluminum foil of 0.1 mm thickness has a charge of that spreads on both wide side...
Related questions
Question
Re write again text form not handwriting. Also need substitutions please do it. 1 and 2. Physics expert
![Required: Flux ($)
Griver, total charge, Ototal
=
8.85×1512 с
Formula used
ф
Statal
=
[Gauss's Theorem]
Eo
Now,
ф
Gostelative permitivity of face space
9total
=
=
Go
8.85×1012
8.85×1012
[60=
"Go = 8.85×1012 (2² Nim²]
⪜
ф =
1 Nm²/c
Hence the srequired flux is 1Nm²/c.
Required: magnitude of the flux
Griven, radius of circular plate, R= 2.2m
Electric field, E = 800 N/C
angle,
(with plane)
0 = 20°
α=70°
Tw
angle
& with normal to the
surface α= 90-20 = 70°
Formula used,
+ = E Acosα
E electric field
Now,
A area
Area of the plate, A = πR² = 3.14 x 2.2²
8% A = 15.2 m²
2
= 3.14×2.2×2.2
electric flux is given by
ф
=
EA cosa
.
The value of required flux is
800 x 15.2 x cos 70°
800x15.2 x 0.342
4158.72 Nm²/c
4158.72 m²/c.
07 4 =
or
0 =
ΟΥ
& =](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa917bcce-fd4c-4ad0-a3b5-845f6a1c8aca%2Ff41d671f-fe4d-4250-96bb-0762740328a2%2F32qgfbf_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Required: Flux ($)
Griver, total charge, Ototal
=
8.85×1512 с
Formula used
ф
Statal
=
[Gauss's Theorem]
Eo
Now,
ф
Gostelative permitivity of face space
9total
=
=
Go
8.85×1012
8.85×1012
[60=
"Go = 8.85×1012 (2² Nim²]
⪜
ф =
1 Nm²/c
Hence the srequired flux is 1Nm²/c.
Required: magnitude of the flux
Griven, radius of circular plate, R= 2.2m
Electric field, E = 800 N/C
angle,
(with plane)
0 = 20°
α=70°
Tw
angle
& with normal to the
surface α= 90-20 = 70°
Formula used,
+ = E Acosα
E electric field
Now,
A area
Area of the plate, A = πR² = 3.14 x 2.2²
8% A = 15.2 m²
2
= 3.14×2.2×2.2
electric flux is given by
ф
=
EA cosa
.
The value of required flux is
800 x 15.2 x cos 70°
800x15.2 x 0.342
4158.72 Nm²/c
4158.72 m²/c.
07 4 =
or
0 =
ΟΥ
& =
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 3 steps with 2 images
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Recommended textbooks for you
College Physics
Physics
ISBN:
9781305952300
Author:
Raymond A. Serway, Chris Vuille
Publisher:
Cengage Learning
College Physics
Physics
ISBN:
9781305952300
Author:
Raymond A. Serway, Chris Vuille
Publisher:
Cengage Learning