(II) A sled is initially given a shove up a frictionless 23.0°incline. It reaches a maximum vertical height 1.22 m higherthan where it started at the bottom. What was its initial speed?

Q: While a roofer is working on a roof that slants at 42.0 ∘∘ above the horizontal, he accidentally…

A:

Q: A 2.1 x 103 - kg car starts from rest at the top of a 5.0 - m - longdriveway that is inclined at…

A: Frictional force is opposite to direction of motion of the car as shown in the figure.

Q: An elevalor has a mass of 2500 kg. Calculate the power required to lift it a vertical distance of 50…

A: given kg mass is 2500 kg accelaration due to gravity is 9.81 m/s distance travelled is 50 m time…

Q: At full power, how long for the car to accelerate 0-64.0mph? Neglecting friction and air resistance

A: Use the expression for the power, apply work-energy theorem, and solve for the power provided by the…

Q: An elevator weighing 3000N ascends at a constant speed of 8.omis. How much power must the motor…

A: Given : Force (F) = 3000 N Speed (v) = 8.0 m/s

Q: A ball of mass 0.320 kg is thrown upward, rising 12.1 m above the point at which it was released.…

A:

Q: A 2.1 × 103 -kg car starts from rest at the top of a 5.0-m-long driveway that is inclined at 20°…

A: Given data: Mass of car, m = 2.1 × 103 kg Length of driveway, L = 5 m  angle of inclination, θ = 20°…

Q: A cyclist coasts up a 11.1° slope, traveling 23.0 m along the road to the top of the hill. If the…

A: Data Given ,  Cyclist's initial speed ( V0 ) = 9.50 m/s Distance travels along the road to the top…

Q: OnEarth,in the absence of air friction, a rock thrown vertically upward at a velocity of 64 feet per…

A: Given, Velocity v = 64 feet s(t)=64t-16t2 .....(1)   Differentiating equation (1)…

Q: An elevator weighing 2500 N ascends at a constant speed of 8.0 m/s. How much power must the motor…

A:

Q: Calculate the work needed for a 65 kg tourist to climb to the top of the great pyramid in Egypt with…

A: The net force acting on an object is equal to the mass times the acceleration of the object. This is…

Q: Repeat Problem 6.30 if the distance along the incline to the platform is 7.0 m and a friction force…

A: Given data:  Mass of cart (m) = 200 kg Vertical height (h) = 1.5 m Distance along the incline (d) =…

Q: A cyclist is working at a rate of 0.20 kW when he is ascending a hill at a constant speed of 18 km…

A: Working rate = power = 0.20 kW  Speed = v = 18km/h = 5 m/s Mass of cyclists and bicycle = m = 80 kg…

Q: A waterslide is 42m long and has a vertical drop of 12m. If a 60kg woman starts down the slide with…

A:

Q: A constant 15 N force is applied at an angle of 45° below the horizontal to a 30 kg cart at rest on…

A: Given that - Force Angle Mass Distance To Find - We have to determine the speed of the cart.

Q: A 60.0 kg skier with an initial speed of 11.0 m/s coasts up a 2.50 m high rise as shown in Figure…

A: The below figure represents the distance travelled up the plane by a 60kg skier with an initai speed…

Q: A ball of mass 0.270 kg is thrown upward, rising 11.1 m above the point at which it was released.…

A: Given:

Q: A block initially at rest slides down a frictionless inclined plane from a height h. It reaches the…

A: Given data: Initial velocity (v0) = 0 m/s Vertical height = h Final speed at bottom of the inclined…

Q: At an amusement park, a swimmer uses a water slide to enterthe main pool. If the swimmer starts at…

A:

Q: A horizontal force of 1.5 N acts on a 0.2kg mass to accelerate it along a horizontal path. How fast…

A:

Q: Constant power P is delivered to a car of mass m by its engine. Show that if air resistance can be…

A:

Q: The engine in an imaginary sports car can provide constant power to the wheels over a range of…

A: u=0 mphv=30 mph=30×1609.343600=13.4 m/sv'=60 mph=2×v=26.8 m/st1=1.20 st2=?

Q: 3. (II) How much work did the movers do (horizontally) push- ing a 46.0-kg crate 10.3 m across a…

A:

Q: A 2.0-kg mass is released from rest at the top of a plane inclined at 20o above horizontal. If there…

A:

Q: The engine in an imaginary sports car can provide constant power to the wheels over a range of…

A: In the first case at constant power, the power is: P1=0.5mv12tP1=0.5m7021.20 In the second case at…

Q: A 2.0 kg mass is placed against a spring of force constant 800 Nim, which has been co m, as…

A: Given:- The force constant of the spring is k = 800 N/m  The compression of the spring d = 0.22 m…

Q: What is the minimum work required to a slide a 20 kg box a 35 degree incline if the incline is 2…

A:

Q: 2 kg is he ld at the top of plane mass t 30 to the herizontal The frilly Irnclined dingenon.…

A:

Q: A 2.1 x 103-kg car starts from rest at the top of a 5.5-m-long driveway that is inclined at 15° with…

A: Given Data : The mass of the car is given as M=2.1×103 Kg The length of the driveway is given as D =…

Q: A man of mass 60.0 kg takes 4 seconds to run up a 4-m high stairs. Which of the following gives the…

A:

Q: What is the power of the force required to move a 4500 kg elevator cab with a load of 1800 kg upward…

A:

Q: - A moving object whose initial KE is 10 J is subject to a frictional force of 2 N that acts in the…

A: Given data:  Initial kinetic energy (KEi) = 10 J Final kinetic energy (KEf) = 0 J Force (F) = 2 N…

Q: A skydiver of mass 60kg is falling at a terminal velocity of 80m/s. How much power is gravity…

A: Given that :m=60 kgv=80 m/shere,m is the mass of the skydiver, andv is the terminal velocity

Q: Compute the minimum power necessary to operate a ski lift that carries skiers along a 45.0 slope.…

A: Given value--- slope = 45 degree.  weight = 700 N. speed = 5 m/s. No. of skiers = 100 . We have to…

Q: A pushing force of 10 000 N is applied to the backside of a car at an angle of 25.0° above the…

A: Force F = 10000N Horizontal angle θ=25∘ Distance s =15 m Mass of the car m = 2250 Kg

Q: A shopper in a supermarket pushes a trolley with a force of 40N directed at an angle of 35° downward…

A:

Q: A 55-kg skier starts from rest at the top of a ski jump, point A in Fig. 6–48, and travels down the…

A: The net force, K.EA+P.EA=K.EB+P.EB12mvA2+mghA=12mvB2+mghB   Rearrange the above equation for the…

Q: . Find the work done on a lagage of 50 kg. pulled by a string elevated at 45 degrees by force of 100…

A: Given that: F=100Nθ=450d=10 mm=50 kgW=?

Q: A man on a motorcycle plans to make a jump as shown in the figure.   If he leaves the ramp with a…

A: Given that -  Initial velocity=v=28 msHorizontal component=vx=25.6 ms As we know,  vx=vcosθ…

Q: While a roofer is working on a roof that slants at 32° above the horizontal, he accidentally nudges…

A:

Q: A shopper in a supermarket pushes a trolley with a force of 40N directed at an angle of 35° downward…

A:

Q: A mass of 2.12 kg is initially at rest upon a frictionless incline with a 33.2 degree angle of…

A:

Q: A mass of 2.0kgis projected with a speed of 5.5m/sup a plane inclined 20 degrees with the…

A:

Q: Why does a bicyclist pick up speed on a downhill road even when he is not pedaling? Does this…

A:

Q: Find out the work done when a force done of 20N displaces a body through 8m in the direction of the…

A: Write the expression for the work done.

Spring Potential Energy

The potential energy is the energy possessed by a body by virtue of its position or the energy held by the object due to its position relative to other objects, its force like stresses, charge, and other factors affecting the particles of the body. The potential energy is the measure of the net work done by or on the body. The spring potential energy is the potential energy stored due to the deformation of an elastic spring and this elasticity is due to the stretched spring. The elasticity is the ability of a solid-state matter to come back to its equilibrium position or original position after any kind of external force is acted on it. It is also known as Elastic potential energy. The potential energy here is caused due to the displacement of the spring from its equilibrium position to another position and this potential energy is equal to the net work done due to the stretching of the spring. It also resembles the same mechanics of the oscillation of a simple pendulum, where due to the external force, the object moves from its equilibrium position to its maximum ends and the periodic motion continues till it comes back to the equilibrium position to rest.