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Star A has a temperature of 5,000 K. How much energy per second (in J/s/m2) does it radiate from a square meter of its surface? If the temperature of Star A decreases by a factor of 2, the energy will decrease by a factor of Star B has a temperature that is 5 times higher than Star A. How much more energy per second (compared to Star A) does it radiate from a square meter of its surface? Part 1 of 4 The energy of a star is related to its temperature by E = GT4 where a = 5.67 x 10-8 J/s/m²/K4. Part 2 of 4 To determine how much energy Star A is radiating, we just plug in the temperature to solve for EA. EA = 3/s/m²

Star A has a temperature of 5,000 K. How much energy per second (in J/s/m2) does it radiate from a square meter of its surface? If the temperature of Star A decreases by a factor of 2, the energy will decrease by a factor of Star B has a temperature that is 5 times higher than Star A. How much more energy per second (compared to Star A) does it radiate from a square meter of its surface? Part 1 of 4 The energy of a star is related to its temperature by E = GT4 where a = 5.67 x 10-8 J/s/m²/K4. Part 2 of 4 To determine how much energy Star A is radiating, we just plug in the temperature to solve for EA. EA = 3/s/m²

Stars and Galaxies (MindTap Course List)
Stars and Galaxies (MindTap Course List)
10th Edition
ISBN:9781337399944
Author:Michael A. Seeds
Publisher:Michael A. Seeds
Chapter7: Atoms And Spectra
Section: Chapter Questions
Problem 10P
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Tutorial Star A has a temperature of 5,000 K. How much energy per second (in J/s/m2) does it radiate from a square meter of its surface? If the temperature of Star A decreases by a factor of 2, the energy will decrease by a factor of Star B has a temperature that is 5 times higher than Star A. How much more energy per second (compared to Star A) does it radiate from a square meter of its surface? Part 1 of 4 The energy of a star is related to its temperature by E = GT4 where σ = 5.67 x 10-8 J/s/m2/K4. Part 2 of 4 To determine how much energy Star A is radiating, we just plug in the temperature to solve for EA. EA = J/s/m² Submit Skip (you cannot come back)
Transcribed Image Text:Tutorial Star A has a temperature of 5,000 K. How much energy per second (in J/s/m2) does it radiate from a square meter of its surface? If the temperature of Star A decreases by a factor of 2, the energy will decrease by a factor of Star B has a temperature that is 5 times higher than Star A. How much more energy per second (compared to Star A) does it radiate from a square meter of its surface? Part 1 of 4 The energy of a star is related to its temperature by E = GT4 where σ = 5.67 x 10-8 J/s/m2/K4. Part 2 of 4 To determine how much energy Star A is radiating, we just plug in the temperature to solve for EA. EA = J/s/m² Submit Skip (you cannot come back)
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Star B has a temperature that is 5 times higher than Star A. How much more energy per second (compared to Star A) does it radiate from a square meter of its surface? EA = O(TA) 4 EB = σ(TB)4 Again, we know that Star B's temperature is n times Star A's. TB = nTA EB = σ(NTA) 4 So in terms of Star A's energy, Star B's is: EB = EA
Transcribed Image Text:Star B has a temperature that is 5 times higher than Star A. How much more energy per second (compared to Star A) does it radiate from a square meter of its surface? EA = O(TA) 4 EB = σ(TB)4 Again, we know that Star B's temperature is n times Star A's. TB = nTA EB = σ(NTA) 4 So in terms of Star A's energy, Star B's is: EB = EA
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If the temperature decreases by a factor of 2, how much will the energy decrease? We have two relations for the energy from the two different temperatures. Eold = o(Told) 4 Enew = o(Tnew) 4 We know that if the new temperature is n times less than the old temperature then: Told =nTn Using this in our expression for Eold gives: Eold = n²o(Tnew) 4 1 -Eold En new new = n So, the energy will decrease by a factor of
Transcribed Image Text:If the temperature decreases by a factor of 2, how much will the energy decrease? We have two relations for the energy from the two different temperatures. Eold = o(Told) 4 Enew = o(Tnew) 4 We know that if the new temperature is n times less than the old temperature then: Told =nTn Using this in our expression for Eold gives: Eold = n²o(Tnew) 4 1 -Eold En new new = n So, the energy will decrease by a factor of
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