If E(X) = -2 and V(X) = 6 (i) E (5X – 2) = 5 E(X) – E(2) = (5 x (-2)) – 2 = -12 (ii) V (5X – 2) = 52 V (X) – V (2) = (25 x 6) - 0 = 150 (iii) V(-5X – 2) = (-5)²V(X) – V (2) = (25 × 6) – 0 = 150 (iv) E (X²) =?

Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter11: Differential Equations
Section11.6: Applications Of Differential Equations
Problem 15E: Solve Exercise 14 if a 25 solution of the same mixture is added instead of pure alcohol.
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a " OMANTEL
If E (X) = -2 and V(X) = 6
() Е(5X — 2) 3 5 E(X) — Е(2) — (5x (-2)) — 2 %3D -12
(iї) V(5X — 2) %3D 52 V(X) — V(2) 3 (25 х 6) — 0 %3D150
(iї) V(-5X — 2) %3D (-5)?V(X) — V(2) 3D (25 х 6) —0 %3D 150
(iv) E (X²) =?
Transcribed Image Text:a " OMANTEL If E (X) = -2 and V(X) = 6 () Е(5X — 2) 3 5 E(X) — Е(2) — (5x (-2)) — 2 %3D -12 (iї) V(5X — 2) %3D 52 V(X) — V(2) 3 (25 х 6) — 0 %3D150 (iї) V(-5X — 2) %3D (-5)?V(X) — V(2) 3D (25 х 6) —0 %3D 150 (iv) E (X²) =?
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