from the graph we can see that x=-2,1,3 are roots of equation.
from (i) we have y=(x+2)(x2-4x-12)=(x+2)(x-6)(x+2)
from(ii) we have y=(x-3)(x2+x-2)=(x-3)(x-1)(x+2)therefore this equation have also same roots -2,1,3
also from (iii) we have y=(x-1)(x2-5x-6)=(x-1)(x-6)(x+1)
Step by stepSolved in 2 steps