If 'B' is the network bandwidth, 'L’ is the cable length and 'C' is the speed of the signal propagation, 'e' is the number of contention. slots per frame and 'F’is the frame length, then channel efficiency 'i' is:
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- Peak to peak amplitude = 300 voltsSignal frequency = 200 HzMedium height form factor: 8 level1. What should be the theoretical minimum sampling frequency for the signal to be reconstructed in the receiver without distortion?2. What should be the practical minimum sampling frequency for the signal to be reconstructed in the receiver without distortion?3. In case of using an anti-aliasing filter at the frequency of 200 Hz that you specify before sampling ,What should the theoretical and practical minimum sampling frequency be?4. What is mean square quantation error?5. Calculate the maximum calculation error.6. Calculate the maximum amplitude of the probability distribution function of the quantization error.7. What is the signal to noise ratio?8. What is the theoretical binary transmission rate?9. What is the practical pairwise transmission rate?10. What would be the theoretical maximum sampling frequency?11. What could be the practical maximum sampling frequency?12. What is the maximum…message sign m (t)=10sinc( 400t )and carrier sign c(t)=100cos (2 π fc t) frequency used in modulation. The modulation index is β=6. Accordingly, the frequency deviation and find the bandwidth of the message signal.An analog signal in sine form is intended to be transmitted to the receiver by pulse code modulation.Given below Define the parameters and answer the questions asked from you. *Peak to peak amplitude = xxx volts *Signal frequency = xxx Hz *Medium height form factor: xxx level You will give the value of xxx 1-)What should be the theoretical minimum sampling frequency for the signal to be reconstructed in the receiver without distortion? 2-) What should be the practical minimum sampling frequency for the signal to be recreated in the receiver without distortion? 3-)Before sampling, what should be the theoretical and practical minimum sampling frequency if an anti-aliasing filter is used at the frequency of xxx Hz you specify? 4-)What is the mean square quantization error? 5-)Calculate the maximum quantization error.
- Q2- You are designing a connection mechanism between two programs, sending packets of data over the internet. You are trying to choose a size for the packets to be sent, depending on the capacity of the channel (channel bandwidth). For example, if a channel has a capacity of 10KB, then you can choose a packet size of 10KB, and send one packet, or choose a packet size of 5KB and send two packets...Etc. The problem you face is that the two programs are at two different locations, with two different channel capacities. If the first channel had a capacity of 3201KB, and the second channel had a capacity of 4565KB, find the maximum packet size that is suitable for both channels.Propagation time is equals to a. Distance/Propagation speed b. Propagation speed/Bandwidth c. Message size/ Bandwidth d. Bandwidth/Queuing timePlease solve it correctly and please provide explanation of your answers. Please answer parts g, h and i. A PC and a Web Server are communicating over a TCP connection. The PC had started the three way handshake with the initial sequence number of 3069 . The Web Server's initial sequence number is 4830 . The window size of the PC is 815 bytes and the window size of the Web Server is 463 bytes. Using the third TCP handshake ack segment the PC sends the http request of the size 396 bytes to the Web Server. Then the Web Server answers with 3 segments containing the requested data. The first segment size is 42 bytes and the second segment size is 276 bytes and the third segment size is 146 bytes respectively. The PC receives all three segments within the timer. But unfortunately the second segment was corrupted. So the PC immediately sends an acknowledgement segment. Assume that the PC uses Selective Repeat/Reject ARQ. g) The second segment from webserver was corrupted. So the PC…
- Question 1 Find the most simplified expression for Question 2 – 4 by using the following choices. - v WXY + WXZ + WYZ+XYZ A. WX + WYZ + XYZ XYZ + XY Z+ XYZ +XYZ+ XYZ B. XY +Z v WXYZ + WXYZ+ WX Y + WYZ + YZ C. XY + YZ + WXb) Let's say a networking company uses a compression technique to encode the message before transmitting over the network. Suppose the message contains 6 unique characters of your name and their frequencies are similar to the last 6 non-zero digits of your mobile number. For example, your name is Badhon and the last 6 digits of your mobile number is 123456. So the frequency Frequency (in thousands) Characters B table of characters will be: 2 3 H. 4 Now, if the compression technique used is Huffman Coding instead of variable-length coding, how many bits will be saved in the message? Show the saving percentage. 6.The Hi-Fi modem company has designed a new frequency modulation that can transmit 38400 bits/sec. The baud rate is 4800. How many frequency levels can each interval have? 3. 4. Given a location with 7 bits what is the minimum and maximum value that it can hold A) As an unsigned location B) As a signed location
- Using the matrix A= 1 L-11 -1] 0 decode the received message: -1 4 2 -12 -1 -12 13 26 -265 -14 -23 100 -6 7 -121. (Hint: Assign a number to each letter of the alphabet: A is 1, B is 2, and so on. A space between words is 27). Transmission Message A |Decoded Message Encoding Matrix Decoding MatrixPERL programming Consider a network with some hosts. The traffic from one host to the other is provided. The question is to find the total bytes that are moving in the network from one host to the other and also for all the routes. The total bytes that are transferred for the day is as below. peter ann 1250 peter mary 910 mark mary 1250 peter mary 450 peter andy 2924 paul peter 1218 paul helen 199 The first name is the source host, the second is the destination host and the number is the bytes that are transferred.A messaging system reads message as 4-digit positive integer d1d2d3d4 and stores encoding of the message e1e2e3e4 for security reason. The encoding process is as follows: ei = (di+i) mod 3 For example, if message is 4590, the encoded message is 2101. Read any arbitrary message and display the encoded message in the following format: Original message = Encoded message = language : C