If all else is constant, which of the following results in an increase in the probability of a Type II error? A. The significance level is increased.   B. The standard error is decreased.   C. The probability of a Type II error cannot be increased, only decreased.   D. The true parameter is farther from the null hypothesis.   E. The sample size is decreased.

Suppose the results indicate that the null hypothesis should be rejected; thus, it is possible that a type I error has been committed. Given the type of error made in this situation, what could researchers do to reduce the risk of this error?   Choose a 0.01 significance level, instead of a 0.05 significance level. Increase the sample size.

A new drug to treat a certain condition is being tested. The null hypothesis of the test is that the drug is not effective. For the researchers, the more consequential error would be for the drug to be effective, but the test does not detect the effect. Which of the following should the researchers do to avoid the more consequential error?     Increase the significance level to increase the probability of Type II error. A Increase the significance level to decrease the probability of Type II error. B Decrease the significance level to increase the probability of Type II error. C Decrease the significance level to decrease the probability of Type II error. D Decrease the significance level to decrease the standard error.

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A disadvantage of running multiple t-tests in the comparison of several population slopes is:   a. the probability of incorrectly rejecting at least one of the hypotheses increases as the number of t-tests increases.   b. the significance level may have to be set as high as 0.10 for valid testing.   c. sample sizes may have to be very large.   d. the null hypothesis may be rejected for any of the t-tests, so a large amount of work was done with nothing gained.   e. All of the above.

Test the claim that the mean GPA of night students is significantly different than 2.1 at the 0.01 significance level.The null and alternative hypothesis would be: _____ H0:p≤0.525 H1:p>0.525 _____ H0:μ≥2.1 H1:μ<2.1 _____ H0:p≥0.525 H1:p<0.525 _____ H0:μ≤2.1 H1:μ>2.1 _____H0:μ=2.1 H1:μ≠2.1 _____ H0:p=0.525 H1:p≠0.525 The test is: ____ two-tailed ____ right-railed ____ left-tailed Based on a sample of 80 people, the sample mean GPA was 2.14 with a standard deviation of 0.05 The test statistic is: ____________ (to 2 decimals) The p-value is: _____________ (to 2 decimals) Based on this we: ______ Reject the null hypothesis ______ Fail to reject the null hypothesis

Test the claim that the mean GPA of night students is smaller than 2.5 at the 0.10 significance level. The null and alternative hypothesis would be: Но:р — 0.625 Но:р 0.625 Но:> 2.5 Но: д %3 2.5 Но: н 0.625 Н:р 2.5 The test is: right-tailed two-tailed left-tailed Based on a sample of 55 people, the sample mean GPA was 2.47 with a standard deviation of 0.03 The p-value is: (to 2 decimals) Based on this we: O Reject the null hypothesis O Fail to reject the null hypothesis

Test the claim that the proportion of people who own cats is significantly different than 30% at the 0.01 significance level. The null and alternative hypothesis would be: 0.3 Но: р > 0.3 Но:р > 0.3 Но:р — 0.3 Но:р 0.3 H1 :µ + 0.3 H1: H 0.3 The test is: two-tailed right-tailed left-tailed Based on a sample of 800 people, 39% owned cats The p-value is: (to 2 decimals) Based on this we: Fail to reject the null hypothesis Reject the null hypothesis

Test the claim that the proportion of people who own cats is significantly different than 10% at the 0.1 significance level. The null and alternative hypothesis would be: 0.1 Ha:p= 0.1 Hop 2 0.1 Ha p 0.1 H,:p 0.1 H, p 0.1 H,:p 0.1 H. p< 0.1 The test is: left-tailed two-tailed right-tailed Based on a sample of 700 people, 19% owned cats The p-value is: (to 2 decimals) Based on this we: Reject the null hypothesis Fail to reject the null hypothesis

Test the claim that the proportion of people who own cats is significantly different than 20% at the 0.02 significance level. The null and alternative hypothesis would be: Ho: 0.2 Ho:p 0.2 Ho: 0.2 O O O The test is: left-tailed two-tailed right-tailed O O Ho:p 0.2 of H₁:p> 0.2 H₁: 0.2 H₁ :p < 0.2 O O Based on a sample of 500 people, 22% owned cats The p-value is: (to 2 decimals)