If all 6.0 x 105 g of carbon (C) is present as C106H263O130N16P, how many moles of C106H263O130N16P are contained in a square kilometer of ocean? How many moles of O2 were produced in producing that C106H263O130N16P?
The full chemical equation for photosynthetic production of algae in seawater is:
106 CO2 + 16HNO3 + 1 H3PO4 + 122 H2O ==> 1 C106H263O130N16P + 138 O2
where the compound C106H263O130N16P (molec. mass 3870 g/mole) represents the average atomic composition of algae. (Paytan and McLaughlin, The Ocean Phosphorous Cycle, Chem. Rev., 107, 563-576 (2007) 10.1021/cr0503613)
On average, there is approximately 6.0 x 105 g of carbon (C) present in a square kilometer of ocean (Arteaga et al., Seasonal modulation of phytoplankton biomass in the Southern Ocean, Nature Communications, 11, Article number: 5364 (2020) 10.1038/s41467-020-19157-2).
If all 6.0 x 105 g of carbon (C) is present as C106H263O130N16P, how many moles of C106H263O130N16P are contained in a square kilometer of ocean?
How many moles of O2 were produced in producing that C106H263O130N16P?
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 1 images
