If a test tube has boiled saliva + potato chips, what did the boiling do to the enzyme in the test tube?
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If a test tube has boiled saliva + potato chips, what did the boiling do to the enzyme in the test tube?
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- A student performed an invertase activity assay on samples from a purification. All reactions occurred in a reaction volume of 100 µL and lasted 3.1 minutes. For each reaction, 5.00 µL enzyme was mixed with 50.0 mM sucrose in 10.0 mM acetate pH 4.8. Then 400 µL of DNS was added, the samples were heated to 90 °C for 5 minutes, and 500 µL of 50.0 mM acetate pH 4.8 was added before loading a 96 well plate in triplicate. Samples were measured at 540 nm using a path length of 0.680 cm. The fraction with the highest activity had A540 of 0.904. The standard of 14.00 mM hydrolyzed sucrose had A540 of 1.047 (the concentration given is of the 100 µL sample). The no-enzyme control had A540 of 0.174. Calculate the activity of the fraction (in nmol min-1).You are testing a river water sample. Your "original" plate shows 100 coliform colonies. Assuming you did the serial dilution correctly, how many coliform colonies would you expect to see on your 1:10 plate? Your 1:100 plate? Explain.Ex. 5-4 Catalase 1) In the Catalase test (5-4), if bacteria was added to hydrogen peroxide on the slide, it might produce a false result. 2) Explain why adding bacteria to the hydrogen peroxide on a slide rather than adding the hydrogen peroxide to the bacteria on the slide might give a false result? 3) Would the false result be a false positive or would the false result be a false negative?
- The arrowhead shaped zone shows what reaction? How do you set up the test for this reaction? For which organism is this an important test?Given this, if you used 6g of vitamin Z powder to make 20 ml of solution, what is the % concentration of this solution? (I gave the image since I don't know if that info is needed to solve this question.)It also gives a follow-up, if you can help here too: You work in a lab as a summer student. One of your tasks is to make sure that there is enough cell culture medium containing antibiotics to grow bacteria. One day you realize that there is only 5 ml of 10% Antibiotic stock solution in the freezer. You decide to use it all to prepare the working culture medium with 0.01% antibiotic. In the lab there is plenty of growth medium without antibiotics. (Note: dilution in medium is like dilution in water). You remember the equation to make dilutions of stock solutions. You usually use this formula to calculate the required volume of a stock solution, but you realize it can apply here as well, even though the unknown is the final volume. So, you make that dilution. Given that each bacterial…In a lab experiment, there was yeast added to four different test tubes. One tube has water, one has glucose, one has sucrose, and the last one has starch. What solution would be the positive control?
- AsapYou are performing an enzyme reaction that works the same way as your wheat germ acid phosphatase (WGAP) assay. First, you dissolve 10.0 umol of product into 1.00 ml of buffer, and measure an absorbance of 0.500. Your cuvette has a 1.00 cm pathlength. Next, you perform the enzyme assay. Your enzyme solution has a concentration of 20.0 ug/ml. 1) Mix 0.250 ml substrate buffer with 0.250 ml enzyme 2) Incubate 20.0 min 3) Stop the assay with 0.500 ml NaOH 4) Read an absorbance of 0.200 *The units required for each answer in this problem are given. Answers to all three parts should be rounded to a maximum of three decimal places. Do not enter any letters. What is the extinction coefficient (ml/umol/cm) of the product? What is the catalytic activity (umol/min) measured in your assay? What is the specific activity (umol/min/ug) measured in your assay?You measure your E. coli and find them to have an OD600 of 1.20. You have 50 ml of culture, and you know that there are 2.5x109 cells per 1.0 OD600. Based on this information, how many E. coli cells are present in the culture you’re about to centrifuge?