Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN: 9780134580999
Author: Elaine N. Marieb, Katja N. Hoehn
Publisher: PEARSON
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- In one of his experiments, Mendel crossed homozygous yellow plants with homozygous green plants. The resulting F1 generation was allowed to self-fertilize. The F2 generation produced 930 yellow seeds and 305 green seeds. What are the genotypes of this F2 generation? O YY : yy O Yy : yy O Yy: yy O YY: Yy : yyarrow_forwardCystic fibrosis (CF) is an autosomal recessive trait. A three-generation pedigree is shown below for a family that carries the mutant allele for cystic fibrosis. Note that carriers are not colored in to allow you to figure out their genotypes. Normal allele = F CF mutant allele = f What is the genotype of individual #13? A) ff B) FF C) Ff D) it is impossible to tellarrow_forwardIn the USA the frequency of carriers for the devastating autosomal recessive trait of procrastination is 1/10 people. You do not procrastinate and want to have a child with another highly efficient non-procrastinator. You are worried that you both might be carriers and that your child would be a procrastinator. What is the probability that you are a carrier, AND your mate is a carrier, AND your child is procrastinator?arrow_forward
- Example: Linkage - Drosophila Body Color / Eye Color Please choose two parent genotypes of dissimilar gender by dragging them into the parent cells at right. Then select check boxes to identify nonrecombinent and recombinent offspring. Click the clear button if you would like to start over. Xy+w+ xyw Xyw y (Xy+W+ хуш) (XyW+ xy+W) (Xyw y) Nonrecombinent phenotypes: Nonrecombinent genotype: Recombinent genotype: Female/males with gray body/red eyes; females/males with yellow body/white eyes. Female/male with gray body/white eyes; female/male with yellow body/red eyes. Female/male with gray body/white eyes; female/male with yellow body/red eyes. Female/male with gray body/red eyes; female/male with yellow body/white eyes. Clear Recombinent phenotypes: Help Xy+w+ xyw Xy+w xyw XyW+ xyw Xyw xyw Xy+w+y Xy+wy XyW+ y Xyw y Submitarrow_forwardSuppose a geneticist is using a three-point test cross to map three linked rabbit morphology and behavioral mutations called si, sf, and H. The gene si is associated with the silky fur phenotype, and sf is associated with the short-footed phenotype. Both si and sf are recessive mutations with respect to wild type. H is a dominant mutation that confers the hyper phenotype. The geneticist first crosses true-breeding hyper rabbits to true-breeding silky fur, short-footed rabbits. Next, the geneticist backcrosses the F₁ progeny to the silky fur, short-footed parents, and obtains the results reported in the table. Phenotype hyper silky fur, short-footed short-footed silky fur, hyper silky fur short-footed, hyper silky fur, short-footed, hyper wild type Place the genes in the correct order in the chromosome. LLIIN HEL H Number 815 807 175 169 4 5 27 29 Answer Bank si sfarrow_forwardColor blindness is typically an inherited genetic condition in which individuals have a decreased ability to see color or differences in color. Color blindness only occurs in individuals who have two recessive alleles for the condition. Normal color vision is due to a dominant allele (C) Color blindness is due to the recessive allele (c) a) If Susan is homozygous for normal vision, and Matt is homozygous for color blindness, what is the likelihood (in percentage) that their son Alex will have color blindness? Perform a Punnett Square (either below or by hand on paper) to find the probability. Provide your answer in a full sentence. If you did the Punnett Square by hand, attach your photo to the next question.arrow_forward
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