If a data set has 25 values and a standard deviation of 7.4, then the variance is?

Given that age of ECU students is normally distributed. A random sample of 16 students had an average age of 25 years and a variance of 4 square years. The 98% CI for the true average age of all ECU students is?

The goal of analysis of variance (ANOVA) is toa. detect differences in treatment variances (or variances for different populations).b. detect differences in treatment means (or means for different populations).c. analyze the average variances for different populations.d. analyze the variances of the variances for different populations.

A successful basketball player has a height of 6 feet 11 ​inches, or 211 cm. Based on statistics from a data​ set, his height converts to the z score of 5.17. How many standard deviations is his height above the​ mean?

Actuaries use various parameters when evaluating the cost of a life insurance policy. The variance of the life spans of a population is one of the parameters used for the evaluation. Each year, the actuaries at a particular insurance company randomly sample 30 people who died during the year (with the samples chosen independently from year to year) to see whether the variance of life spans has changed. The life span data from this year and from last year are summarized below. Current Last Year Year x1 = 75.8 | x,= 76.2 si= 47.61 s3= = 92.16 (The first row gives the sample means and the second row gives the sample variances.) Assume that life spans are approximately normally distributed for each of the populations of people who died this year and people who died last year. Can we conclude, at the 0.05 significance level, that the variance of the life span for the current year, of, differs from the variance of the life span for last year, o,? Perform a two-tailed test. Then complete the…

Actuaries use various parameters when evaluating the cost of a life insurance policy. The variance of the life spans of a population is one of the parameters used for the evaluation. Each year, the actuaries at a particular insurance company randomly sample 30 people who died during the year (with the samples chosen independently from year to year) to see whether the variance of life spans has changed. The life span data from this year and from last year are summarized below. Current Last Year Year *1 = 75.8 x2 = 76.2 s3 = 47.61 s3= 92.16 (The first row gives the sample means and the second row gives the sample variances.) Assume that life spans are approximately normally distributed for each of the populations of people who died this year and people who died last year. Can we conclude, at the 0.05 significance level, that the variance of the life span for the current year, of, differs from the variance of the life span for last year, o,? Perform a two-tailed test. Then complete the…

Part 1. .If b = 0.523, then for every 1 unit increase in the independent variable, there is a 0.523 unit increase in the dependent variable. True or false?   2. .If b = .704, then 70.4% of the variance in the dependent variable can be explained by the variance in the independent variable. In contrast, 29.6% of the variance in the dependent variable can be explained by outside factors. True or false? 3. .If r = 0.444, then for every 1 unit increase in the independent variable, there is a 0.444 unit increase in the dependent variable. True or false?

The mean square error is the variance plus the bias. True O False

It is possible to have a variance of 625,000625,000 for some data set. true or false

the homogeneity of variances assumption states that the variance in the two samples must be equal? true