If a 0.450-kg object (m1) is connected to a 0.0400-kg mass (m2) (see in Figure 1) and a constant frictional force of 0.100 N acts on the object. Solve for the acceleration a.

Block 1 (10 kg) is located on the surface of a table. A rope pulls on block 1 with a horizontal tension of 58 N to the right and a vertical tension of 60N upward. The coefficient of kinetic friction between the block and the surface equals 0.2. On a sheet of paper, draw the free body diagram for block 1 using the two- subscript notation from class. After completing the free body diagram, enter below each force and its x & y-components. Remember that the x-component is the "i" component and the y-component is the "j" component. FORCES on BLOCK 1 Weight force on block 1 by Earth W1E : jN Tension force on block 1 by Rope T1R = jN %3D Normal force on block 1 by Surface N1S = i+ jN %3D Frictional force on block 1 by Surface f1S = i + jN !! Submit Answer Tries 0/2 What is the acceleration a of block 1? j m/s2 a =

Two blocks each of mass m are fastened to the top of an elevator as in the figure below. The elevator has an upward acceleration a. The strings have negligible mass. (a) Find the tensions T1 and T2 in the upper and lower strings in terms of m, a, and g. T1 =       T2 =       (b) Compare the two tensions and determine which string would break first if a is made sufficient large.

Please help me solve #1

Consider a car heading down a 6.5° slope (one that makes an angle of 6.5° with the horizontal) under the following road conditions. You may assume that the weight of the car is evenly distributed on all four tires and that the coefficient of static friction is involved—that is, the tires are not allowed to slip during the acceleration. Use a coordinate system in which down the slope is positive acceleration. 1.) calculate the max acceleration for the car on dry concrete in m/s^2? 2.) calculate the max acceleration on wet concrete? 3.) calculate max acceleration for the car on ice, assuming that Us is 0.100, the same as it is for shoe on ice.

A man of mass 69 kg stands tries to stand on a sloping surface that rises at 20 degrees to the horizontal. Assuming that the man is able to stand still, draw a free body diagram for the man. N = Normal N Number 110 Fg Delete Assuming the man is able to stand still, what would be the magntiude of the frictional force on him? (Give the answer in Newtons-numerical value only, no units) Remaining Time: 03:26:36 nimmt af atatin drintion habınan abana and the dans le 00 14 the man be able to stand hard alidima? Next

A mass of 3.2 kg is initially at rest upon a horizontal surface. An applied force of 42 N i then acts on the mass. If the coefficient of kinetic friction regarding the system is 0.868, what is the magnitude of the object's acceleration? Assume that all quantities are good to 3 significant figures, All numeric answers should be entered rounded to 3 significant figure.

Please proceed with handwritten. Be sure , Don't just try.

Two boxes are connected by a massless string across a massless frictionless pulley.  Box S has a mass M and box H has a mass m. write Newton's 2nd law equation for these objects, horizontal component only for box S and vertical component only for box H. solve algebraically for acceleration of the boxes. given M = 8.4 kg and m = 5.7 kg, use the equation from the previous part to find the value of the acceleration. use this answer to find the tension of the string.

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