College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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- Two blocks are positioned on surfaces, each inclined at the same angle of 55.4 degrees with respect to the horizontal. The blocks are connected by a rope which rests on a frictionless pulley at the top of the inclines as shown, so the blocks can slide together. The mass of the black block is 4.36 kg, and the coefficient of kinetic friction for both blocks and inclines is 0.290. Assume static friction has been overcome and that everything can slide. What is must be the mass of the white block if both blocks are to slide to the LEFT at a constant velocity? 2.91 kg 6.54 kg 4.36 kg 5.45 kgarrow_forwardTwo blocks are positioned on surfaces, each inclined at the same angle of 44.0 degrees with respect to the horizontal. The blocks are connected by a rope which rests on a frictionless pulley at the top of the inclines as shown, so the blocks can slide together. The mass of the black block is 6.84 kg, and the coefficient of kinetic friction for both blocks and inclines is 0.250. Assume static friction has been overcome and that everything can slide. What is must be the mass of the white block if both blocks are to slide to the LEFT at an acceleration of 1.5 m/s^2?arrow_forwardTwo blocks are positioned on surfaces, each inclined at the same angle of 45.1 degrees with respect to the horizontal. The blocks are connected by a rope which rests on a frictionless pulley at the top of the inclines as shown, so the blocks can slide together. The mass of the black block is 7.86 kg, and the coefficient of kinetic friction for both blocks and inclines is 0.540. Assume static friction has been overcome and that everything can slide. What is must be the mass of the white block if both blocks are to slide to the LEFT at a constant velocity? 17.02 kg 2.36 kg 26.17 kg 7.86 kgarrow_forward
- Two blocks are positioned on surfaces, each inclined at the same angle of 40.7 degrees with respect to the horizontal. The blocks are connected by a rope which rests on a frictionless pulley at the top of the inclines as shown, so the blocks can slide together. The mass of the black block is 3.70 kg, and the coefficient of kinetic friction for both blocks and inclines is 0.280. Assume static friction has been overcome and that everything can slide. What is must be the mass of the white block if both blocks are to slide to the RIGHT at an acceleration of 1.5 m/s^2?arrow_forwardTwo blocks are positioned on surfaces, each inclined at the same angle of 52.4 degrees with respect to the horizontal. The blocks are connected by a rope which rests on a frictionless pulley at the top of the inclines as shown, so the blocks can slide together. The mass of the black block is 5.40 kg, and the coefficient of kinetic friction for both blocks and inclines is 0.350. Assume static friction has been overcome and that everything can slide. What is must be the mass of the white block if both blocks are to slide to the RIGHT at an acceleration of 1.5 m/s^2? 1.98 kg 2.55 kg 4.61 kg 2.07 kgarrow_forwardProblem 4: A ball of mass m is connected to two rubber bands of length L, cach under temsion T, as shown in the Figure. Assume the tension does not change. (a) The ball of mass m is in equilibrium. Draw a free-body diagram on m. (b) Since the ball of mass m is in equilibrium, Enet y = 0. Use Fnet.y=0 to find the equilibrium position for the ball yo. Hint: sin 0=yo/L, Answer: yo = mgL/(2T'). |Yo L. T. L т (c) The ball of mass m is now displaced slightly from equilibrium, as shown in the figure below. Draw a free-body diagram on m. (d) Use Newton's 2nd Law: Fnet,y = ma = -m to show that the motion of m satisfies the SHM differential equation + w²u = 0, where u = y – Yo and w = since the downward gravitational force on the ball is larger than the two upward tension forces on the ball. Hint: sin 0 = y/L. Also, from part (b), yo = mgL/(2T). We can rewrite this expression as mg = 2T(yo/L). Use this expression to substitute for mg in Newton's 2nd Law: Fnet.y = -ma = -my | 2T. For this problem…arrow_forward
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