If 60.13g of Nb(s) are added to 125.0ml of a 5.96mL of a 5.96 M solution of HClO4(aq), what is the mass of Nb(ClO4)5(aq) that is produced?
Given that -
Mass of Nb(s) = 60.13 g
Volume of HClO4 Solution = 125.0 mL
Molarity of HClO4 Solution = 5.96 M
The Balanced Chemical equation between HClO4 and Nb is -
10HClO4(aq) + 2Nb(s) ------> 2Nb(ClO4)5(aq) + 5H2
The molar masses of substances are -
HClO4 = 100.46 g/mol
Nb = 92.906 g/mol
Nb(ClO4)5 = 590.159 g/mol
According to this reaction , 10×100.46 g or 10 moles of HClO4 react with 2×92.906 g or 2 moles of Nb to give 2 moles or 2×590.159 g Nb(ClO4)5
Step by stepSolved in 2 steps