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If 0.750 L of argon at 1.50 atm and 177°C is mixed with 0.235 L of sulfur dioxide at 95.0 kPa and 63.0°C in a 1.00-L flask and the flask's temperature is adjusted to 25.0°C, what is the resulting pressure in the flask? 1 atm = 760 torr = 101.325 kPa; R = 0.0821 L.atm/mol.K

If 0.750 L of argon at 1.50 atm and 177°C is mixed with 0.235 L of sulfur dioxide at 95.0 kPa and 63.0°C in a 1.00-L flask and the flask's temperature is adjusted to 25.0°C, what is the resulting pressure in the flask? 1 atm = 760 torr = 101.325 kPa; R = 0.0821 L.atm/mol.K

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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b is correct. Can you please show me how?

If 0.750 L of argon at 1.50 atm and 177°C is mixed with 0.235 L of sulfur dioxide at 95.0 kPa and 63.0°C in a 1.00-L flask and the flask's temperature is adjusted to 25.0°C, what is the resulting pressure in the flask? 1 atm = 760 torr = 101.325 kPa; R = 0.0821 L.atm/mol.K Select one: O a. 0.244 atm O b. 0.940 atm c. 1.86 atm x O d. 0.0851 atm O e. 1.74 atm
Transcribed Image Text:If 0.750 L of argon at 1.50 atm and 177°C is mixed with 0.235 L of sulfur dioxide at 95.0 kPa and 63.0°C in a 1.00-L flask and the flask's temperature is adjusted to 25.0°C, what is the resulting pressure in the flask? 1 atm = 760 torr = 101.325 kPa; R = 0.0821 L.atm/mol.K Select one: O a. 0.244 atm O b. 0.940 atm c. 1.86 atm x O d. 0.0851 atm O e. 1.74 atm
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