Idiot’s Delight is a fairly simple game of solitaire, yet it is difficult to win. The goal is to draw all of the cards from the deck, and end up with no cards left in your hand. You will run through the deck of cards one time. Start by dealing 4 cards to your hand. You will always look at the last 4 cards in your hand. If the ranks of the “outer” pair (1st and 4th) are the same, discard all four cards. Otherwise, if the suits of the “inner” pair (2nd and 3rd) are the same, discard those 2 cards only. If you have less than 4 cards, draw enough to have 4 cards in your hand. If the deck is empty, the game is over. Your score will be the number of cards that remain in your hand. Like in golf, the lower the score the better. Create a new Python module in a file named “idiots_delight.py”. Add a function called deal_hand that creates a standard deck of cards, deals out a single hand of 4 cards and returns both the hand and the deck. Remember that for the last assignment, you created several functions to emulate cards. To help with testing, don’t shuffle the deck at this time. Deal out 4 cards. Add a function called discard that declares parameters for a hand and the number of cards to discard. If the number is not either 4 or 2, or there are less than 4 cards in the hand, simply return the hand. If the number is 4, discard the last 4 cards from the hand, otherwise if the number is 2, discard the 2 inner cards (the 2 before the last card). Return the hand.

You have a pack of 5 randomly numbered cards, which can range from 0-9. You can win if you can produce a higher two-digit number from your cards than your opponent. Return true if your cards win that round. Examples winRound ([2, 5, 2, 6, 9], [3, 7, 3, 1, 2]) → true // Your cards can make the number 96 // Your opponent can make the number 73 // You win the round since 96 > 73 winRound ([2, 5, 2, 6, 9], [3, 7, 3, 1, 2]) → true winRound ([1, 2, 3, 4, 5], [9, 8, 7, 6, 5]) → false winRound ([4, 3, 4, 4, 5], [3, 2, 5, 4, 1]) → false

FaceUp card game In this assignment we will implement a made-up card game we'll call FaceUp. When the game starts, you deal five cards face down. Your goal is to achieve as high a score as possible. Your score only includes cards that are face up. Red cards (hearts and diamonds) award positive points, while black cards (clubs and spades) award negative points. Cards 2-10 have points worth their face value. Cards Jack, Queen, and King have value 10, and Ace is 11. The game is played by flipping over cards, either from face-down to face-up or from face-up to face-down. As you play, you are told your total score (ie, total of the face-up cards) and the total score of the cards that are face down. The challenge is that you only get up to a fixed number of flips and then the game is over. Here is an example of the output from playing the game: FACE-DOWN | FACE-DOWN | FACE-DOWN | FACE-DOWN | FACE-DOWN Face up total: 0 Face down total: -5 Number of flips left: 5 Pick a card to flip between 1…

You will build a simplified, one-player version of the classic board game Battleship! In this version of the game, there will be a single ship hidden in a random location on a 5 × 5 grid. The player will have 4 guesses at most to try to sink the ship. At each guess, the player names an attacking coordinate, that is (“guess row”, “guess col”). The game ends in two conditions: (1) the player is out of guesses; (2) the player hits the ship. Examples are given in Figure 1. The 5 × 5 board is shown every time the player inputs a guess entry. The ship takes only one entry of the board and it is randomly given before the player’s guesses. The player inputs guessing entries in the Python console. Entries missed the ship are replaced by “X” in the board. You must use loop in your code. Please submit your code and console screenshots to bartleby. Code contain- ing syntax error will be graded zero. Hints: 1 Create a variable board and set it equal to an empty list…

: You will build a simplified, one-player version of the classic board game Battleship! In this version of the game, there will be a single ship hidden in a random location on a 5 °ø 5 grid. The player will have 4 guesses at most to try to sink the ship. At each guess, the player names an attacking coordinate, that is (“guessrow”, “guess col”). The game ends in two conditions: (1) the player is out of guesses; (2) the player hits the ship. Examples are given in Figure 1. § The 5 X 5 board is shown every time the player inputs a guess entry. § The ship takes only one entry of the board, and it is randomly given before the player’s guesses. § The player inputs guessing entries in the Python console. § Entries that missed the ship are replaced by “X” on the board. § You must use a loop in your code. § Please submit your code and console screenshots to Blackboard. Code containing syntax error will be graded zero. Hints: 1. Create a variable board and set it equal to an empty list and…

canMove(int x, int y, int destX, int destY, Side s): This method returns true if the player of color s can move the piece at coordinates (x,y) can move to coordinates (destX, destY) on the board in its current state. This means that here you do need to consider this piece’s interaction with other pieces on the board. Conditions for this method to return false are given in the code.   public boolean canMove(int x, int y, int destX, int destY, Side s){        /* TODO write a method that checks if a piece at coordinates x,y can move to coordinates destX,destY        Conditions for false:        - Origin or destination coordinates are outside the board        - Piece at origin is null        - If source and destination coordinates are the same        - Piece at origin is not of the same side as s             - You can check this using piece.getSide()        - Piece cannot move to the destination by piece movement rules             - You should check this using Piece.canMove(destX,…

Implement the "Add player" menu option. Prompt the user for a new player's jersey number and rating. Append the values to the two vectors. Ex: Enter a new player's jersey number: 49 Enter the player's rating: 8

Complete the recursive drawBoxes() method so that it will draw all of the boxes in the image below. It currently only draws the first and smallest Box. Feel free to use a different shape if you do not like boxes.